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Sholpan [36]
4 years ago
7

Which number is rational? square root 2 3.4 square root 10 square root 16

Mathematics
1 answer:
IRINA_888 [86]4 years ago
3 0

Answer:

3.4

Step-by-step explanation:

3.4 is able to be converted into a fraction so it is rational.

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On Thursday, Movietown Theater made \dfrac45
Oliga [24]

Answer:

11 Pounds

Step-by-step explanation:

Let the total pounds of popcorn made by Movietown Theater=x

On Thursday, they made \dfrac{4}{5} of their popcorn with butter.

The remaining fraction of the butter will be: 1-\dfrac{4}{5} =\dfrac{1}{5}

The remaining 35.2 Ounces was made without butter.

Let us convert from ounces to pounds.

  • 1 Ounce =0.0625 Pound
  • 35.2 Ounce=35.2 X 0.0625 =2.2 Pounds

Therefore:

\dfrac{1}{5} \text{of the total pounds of popcorn} = 2.2\\\dfrac{1}{5}* x = 2.2\\x=2.2* 5\\x=11 $ Pounds

Therefore, the total pounds of popcorn made by Movietown Theater on Thursday is 11 Pounds.

8 0
3 years ago
I NEED HELP I HAVE 10 MINS LEFT
AlekseyPX

Answer:

either A or D

Step-by-step explanation:

but i think its D

3 0
3 years ago
How many subsets are there of the set N = {1, 42, 65, 12, 31, 27}?
lutik1710 [3]

Answer:

\boxed{ \bold{  \huge{ \boxed{ \sf{64}}}}}

Step-by-step explanation:

If ' n ' is the cardinal number of a set, the number of subsets of a given set can be obtained by using the formula 2ⁿ

Given,

N = { 1 , 42 , 65 , 12 , 31 , 27 }

where n ( total number of elements ) = 6

So, the number of possible subsets of set N :

= 2ⁿ

= 2⁶

= 2 × 2 × 2 × 2 × 2 × 2

= 64

Hope I helped!

Best regards!!

4 0
4 years ago
Identify the class​ width, class​ midpoints, and class boundaries for the given frequency distribution.
Crank

Answer:

a. Class width=4

b.

Class midpoints

46.5

50.5

54.5

58.5

62.5

66.5

70.5

c.

Class boundaries

44.5-48.5

48.5-52.5

52.5-56.5

57.5-60.5

60.5-64.5

64.5-68.5

68.5-72.5

Step-by-step explanation:

There are total 7 classes in the given frequency distribution. By arranging the frequency distribution into the refine form we get,

Class

Interval frequency

45-48 1

49-52 3

53-56 5

57-60 11

61-64 7

65-68 7

69-72 1

a)

Class width is calculated by taking difference of consecutive two upper class limits or two lower class limits.

Class width=49-45=4

b)

The midpoints of each class is calculated by taking average of upper class limit and lower class limit for each class.

M=\frac{lower class limit+upper class limit}{2}

Class

Interval Midpoints

45-48 \frac{45+48}{2}=46.5

49-52 \frac{49+52}{2}=50.5

53-56 \frac{53+56}{2}=54.5

57-60 \frac{57+60}{2}=58.5

61-64 \frac{61+64}{2}=62.5

65-68 \frac{65+68}{2}=66.5

69-72 \frac{69+72}{2}=70.5

c)

Class boundaries are calculated by subtracting 0.5 from the lower class limit and adding 0.5 to the upper class interval.

Class

Interval Class boundary

45-48 44.5-48.5

49-52 48.5-52.5

53-56 52.5-56.5

57-60 56.5-60.5

61-64 60.5-64.5

65-68 64.5-68.5

69-72 68.5-72.5

7 0
3 years ago
Suppose a sample of 60 business majors revealed that the average time spent studying per week is 22 hours with a standard deviat
trapecia [35]
IDK I don't why I'm answering cuz yeah n IDK xD
4 0
4 years ago
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