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joja [24]
3 years ago
12

A triangle can be formed with side lengths 2 in, 3 in, and 6 in. True or False

Mathematics
2 answers:
Zepler [3.9K]3 years ago
8 0
The answer to your question is false
Law Incorporation [45]3 years ago
7 0
False, the sides on the left and right are the same length the bottom is not
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-Ready
sweet [91]

Answer:

32

1/4y=8

(4/1)1/4y=8(4/1)

y=32

4 0
3 years ago
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In right ∆LMN, sin M = 0.759. What is cos N? A. 0.121 B. 0.241 C. 0.349 D. 0.651 E. 0.759
Hatshy [7]

Answer:

E. 0.759

Step-by-step explanation:

You can take this right triangle to have a base length side LM , height of LN and a hypotenuse of MN

The sine of angle ∠LMN is 0.759, find the value of ∠LMN

sin^-1(0.759)=49.38

∠LMN=49.38°

Find angle ∠LNM

You know sum of angles in a triangle add up to 180°, given that this is a right-triangle, the base angle is 90° hence

∠LNM=180°-(90°+49.38°)

∠LNM= 180°-139.38°=40.62°

Find cos 40.62°

Cos 40.62°=0.7590

6 0
3 years ago
The number 16 has two square roots: 4 and
maw [93]

Answer:

4 and -4 are both the square roots of 16

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If you subtract 38431 from a number, you are left with 14391.Find the number
Yakvenalex [24]

Answer:

52822

Step-by-step explanation:

38431+14391= 52822

Hope this helps! :)

5 0
3 years ago
Read 2 more answers
Solve equation, check for extraneous solutions
fiasKO [112]

Start with

1=\dfrac{1}{n^2}+\dfrac{n^2-4n-5}{3n^2}

We observe that both fractions are not defined if n=0. So, we will assume n \neq 0.

We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}

We multiply both sides by 3n^2:

n^2-4n-2=3n^2

We move everything to one side and solve the quadratic equation:

2n^2+4n+2=0 \iff 2(n^2+2n+1)=0 \iff 2(n+1)^2=0 \iff n+1=0 \iff n=-1

We check the solution:

1=\dfrac{1}{1}+\dfrac{1+4-5}{3} \iff 1 = 1+0

which is true

8 0
3 years ago
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