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joja [24]
3 years ago
12

A triangle can be formed with side lengths 2 in, 3 in, and 6 in. True or False

Mathematics
2 answers:
Zepler [3.9K]3 years ago
8 0
The answer to your question is false
Law Incorporation [45]3 years ago
7 0
False, the sides on the left and right are the same length the bottom is not
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Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer
lyudmila [28]

If

f(\theta)=10\cos\theta+5\sin^2\theta

then the derivative is

f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta

Critical points occur where f'(\theta)=0. This happens for

-10\sin\theta+10\sin\theta\cos\theta=0

-10\sin\theta(1-\cos\theta)=0

\implies-10\sin\theta=0\text{ or }1-\cos\theta=0

In the first case, we find

-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi

In the second,

1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi

So all the critical points occur at multiples of \pi, or n\pi. (This includes all the even multiples of \pi.)

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3 years ago
A circular pool is 32 foot across.What is the area of the pool rounded to the nearest hundredth of a foot?___square feet.
liberstina [14]

Answer:

correct answer is 95

clear explanation is 86

7 0
2 years ago
Hey guys so I forgot what an exponent is.<br><br>This is what I put:​
WINSTONCH [101]

Step-by-step explanation:

An exponent is that number multiplied by itself however many times it say

Exp: 10³=10×10×10

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2 years ago
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Read 2 more answers
Given: the function defined by f(x)=3x^2-4 Which statement is true? 1. f(0) = 0 2. f(-2) = f(2) 3. f(5)+ f(2) = f(7) 4. f(5) x f
sergeinik [125]
f(x)=3x^2-4 \\ \Downarrow \\ f(0)=3 \times 0^2-4=0-4=-4 \\ -4 \not= 0 \\ f(0) \not= 0 \\&#10;\hbox{statement 1 is false} \\ \\&#10;f(-2)=3 \times (-2)^2-4 =3 \times 4-4=12-4=8 \\&#10;f(2)=3 \times 2^2-4=3 \times 4-4=12-4=8 \\ 8=8&#10;\\ f(-2)=f(2) \\&#10;\hbox{statement 2 is true}

f(5)=3 \times 5^2-4=3 \times 25-4=75-4=71 \\ f(2)=8 \\&#10;f(7)=3 \times 7^2-4=3 \times 49-4=147-4=143 \\&#10;71+8 \not= 143 \\&#10;f(5)+f(2) \not= f(7) \\ \hbox{statement 3 is false} \\ \\&#10;f(5)=71 \\ f(2)=8 \\ f(10)=3 \times 10^2-4=3 \times 100-4=300-4=296 \\&#10;71 \times 8 \not= 296 \\&#10;f(5) \times f(2) \not= f(10) \\&#10;\hbox{statement 4 is false}

Stamement 2. f(-2)=f(2) is true.
3 0
3 years ago
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