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torisob [31]
3 years ago
7

Solve 12^x-2=20 round to the nearest ten-thousandth

Mathematics
2 answers:
Sergio [31]3 years ago
8 0

Answer:

x = 1.2439

Step-by-step explanation:

The equation given is:

12^{x} - 2 = 20

Simplifying this, we have:

12^x = 20 + 2\\\\\\12^x = 22

To solve this, we have to convert it from index form to logarithmic form:

log_{12}22 = x

Using one of the laws of logarithm, we have that:

\frac{log_{10}22}{log_{10}12} = x

This will give us:

\frac{1.3424}{1.0792} = x\\\\\\1.2439 = x

=> x = 1.2439

LUCKY_DIMON [66]3 years ago
4 0
12^x = 22 
<span>x * log 12 = log 22 </span>
finsih that then you round it to the nearest thousandth 
that's what i learnt.
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\huge \underline \mathcal{Answer}

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Therefore,

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