Answer:
32 meters
Explanation:
Given:
x₀ = 0 m
y₀ = 1 m
y = 1 m
v₀ₓ = 18 cos 52° m/s
v₀ᵧ = 18 sin 52° m/s
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
Find: x
First, find the time it takes for the ball to be caught.
y = y₀ + v₀ᵧ t + ½ aᵧt²
1 = 1 + 18 sin 52° t + ½ (-9.8) t²
0 = 14.2 t − 4.9 t²
0 = t (14.2 − 4.9 t)
t = 0 or 2.89
It takes 2.89 seconds to be caught. The horizontal distance traveled in that time is:
x = x₀ + v₀ₓ t + ½ aₓt²
x = 0 + (18 cos 52°) (2.89) + ½ (0) (2.89)²
x = 32.1
Rounded to two significant figures, the ball travels 32 meters.
Answer:
Explanation:
Mathematically, linear momentum is expressed as the product of mass and velocity. Linear momentum conservation law states that a body or system of bodies retains its total momentum unless an external force is applied to the system.
In this case, the system consists of two carts.
At the start, the linear momentum (P) of the system is equal to:

It's only composed of linear momentum of the standard cart because cart A doesn't have any linear momentum at that moment.
After the collision, linear momentum has to be the same

where m_A is the mass of the cart A.
Solving for m_A

After the cart A rebounds, the linea momentum of the system has changed (because of the force present in the rebound). The new linear momentum is:

Then, the lump of putty is added to the system, but the linear momentum has to be the same, because we added a mass, not a force. The mass of that putty (m_p) has to be added to the equation of the system

Solving for m_p

Answer:
4
Explanation:
friction
weight
normal reaction
force to overcome inertia
Answer:
A motion diagram represents the motion of an object by displaying its location at various equally spaced times on the same diagram. Motion diagrams are a pictorial description of an object's motion. They show an object's position and velocity initially and present several spots in the center of the diagram.
Explanation:
an object moves along a straight line, the distance travelled can be represented by a distance-time graph. In a distance-time graph, the gradient of the line is equal to the speed of the object. The greater the gradient (and the steeper the line) the faster the object is moving