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Sophie [7]
3 years ago
15

What element is oco in physics

Physics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0
It is carbon dioxide! Hope this helps you!
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Answer:

Carbon Dioxide

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The bell rings and a physics student heads to class. They stop to talk to a few friends. They slow
grin007 [14]

Answer:

420m

Explanation:

Given parameters:

Time  = 5minutes

Average speed  = 1.4m/s

Unknown:

Distance covered  = ?

Solution:

Speed is the rate of change of distance with time.

 Mathematically;

              Speed  = \frac{distance}{time}  

    Distance  = speed x time

 

Insert the parameters and solve;

   Convert the time to seconds;

              1 minute = 60s

               5 minute = 5  x 60 = 300s

So,

   Insert the parameters and find the distance;

     Distance  = 300 x 1.4  = 420m

3 0
3 years ago
Students will explain, distinguish the difference between the 4 states of matter
vitfil [10]
What?                                what what what what
7 0
3 years ago
Which of the following is not an example I work?? Some please help
n200080 [17]
B. picking up a box off the floor
8 0
4 years ago
Read 2 more answers
Daniel has a sample of pure copper. Its mass is 89.6 grams (g), and its volume is 10 cubic centimeters (cm3). What’s the density
adell [148]
The correct answer is 8.96gl/cm^3*
5 0
3 years ago
1. A race car moves along a circular track of radius 100m at a velocity of 25m/s. (a) What is
goldenfox [79]

Given :

A race car moves along a circular track of radius 100m at a velocity of 25m/s.

To Find :

(a) What is  the time taken to complete one lap of the circular track.

(b) What is the time taken for 10  laps.

Solution :

Circumference of circular track,

C = 2\pi r\\\\C = 2\times \pi \times 100\ m\\\\C = 628.32 \ m

a) Time taken to complete one lap is :

t= \dfrac{628.32}{25}\ s\\\\t =25.13 \ s

b) Time taken to complete 10 laps is :

t_{10} = 10\times t\\\\t_{10} = 10\times 25.13\ s\\\\t_{10} = 251.3\ s

Hence, this is the required solution.

6 0
3 years ago
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