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balandron [24]
3 years ago
10

You can drive your car at 21.7 miles with one gallon of gasoline. At this rate how many miles can you drive with 13.2 gallons of

gasoline
Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:

267.344 miles

Step-by-step explanation:

21.7 miles * 13.2 gallons= 267.344 miles

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Z^5=-243i, find the solution to the equation whose argument is strictly between 180 degrees and 270 degrees. Round your answer t
11Alexandr11 [23.1K]

Answer:

The solution is z = -2.853 - i 0.927.

Step-by-step explanation:

Complex power is determined by means of the De Moivre's Theorem, whose expression is:

z^{n} = r^{n} \cdot (\cos n\theta + i \sin n\theta)

Where r is the norm of the complex number. In this case, expression can be written as:

-i 243 = 3^{5} \cdot (\cos 5\theta + i \sin 5\theta)

The real component must be equal to zero and complex component must be equal to -1. That is to say:

\cos 5\theta = 0

\sin 5\theta = -1

Possible solutions for each component are, respectively:

Real component

5\theta = \cos^{-1}0

5\theta = \frac{\pi}{2} \pm \pi\cdot j, \forall j \in \mathbb{N}_{O}

\theta = \frac{\pi}{10} \pm \frac{\pi}{5}  \cdot j, \forall j \in \mathbb{N}_{O}

Possible solutions: \frac{11\pi}{10}, \frac{13\pi}{10}, \frac{3\pi}{2}

Complex component

5\theta = \sin^{-1}(-1)

5\theta = \frac{3\pi}{2} \pm 2\pi \cdot j, \forall j \in \mathbb{N}_{O}

\theta = \frac{3\pi}{10} \pm \frac{2\pi}{5}  \cdot j, \forall j \in \mathbb{N}_{O}

Possible solutions: \frac{11\pi}{10}, \frac{3\pi}{2}

There is one solution whose argument is strictly between 180 degrees (\pi) and 270 degrees (1.5\pi).

z = 3 \cdot \left( \cos \frac{11\pi}{10} + i \sin \frac{11\pi}{10} \right)

z = -2.853 - i 0.927

6 0
3 years ago
Which function, when graphed, would contain all the points in the table below? x 0,-1,-4 y 0,1,2
galina1969 [7]
Let's take a look at the <em>relationship</em> between x and y in this function. When we look at the first non-zero pair, (-1, 1), we can see that, in the transition from x to y, our x value was had to have been multiplied by -1. For now, we could tentatively say that y = -x. Unfortunately, the next pair, (-4, 2), debunks this hypothesis pretty quickly, as 2 ≠ -(-4). We'll need to reexamine the relationship between x and y here.

One patter that we can be fairly confident in is that multiplication by -1; the sign is flipped from negative to positive when we go from x to y in each case, so we can hold onto that component of the function. Something else is happening before that sign flip, though, and we'll need to look into that by seeing how else the numbers are connected.

Ignoring the negative signs for a moment, let's take a look at the pairs (1,1) and (4, 2). We can transform 1 to 1 pretty easily; we simply multiply or divide it by 1. From 4 to 2, we can either divide it by 2 or multiply it by 1/2. Let's thing in terms of division for now. We know that

1/1 = 1 (obviously)
4/2 = 2

We might have something here! It looks like the number we divide by and the number we obtain are the same, so let's explore this further. Multiplying both sides by those denominators, we find:

1 = 1²
4 = 2²

Almost there! To finally find the relationship, we just square root both sides to get:

√1 = 1
√4 = 2

So that was the function we'd been looking for - a square root! Putting that together with what we said about changing the sign at the beginning, we have:

y =√(-x)

To verify this, we just need to plug in a few pairs, and we find that indeed:

1 = √-(-1) = √1 = 1
2 = √-(-4) = √4 = 2
7 0
4 years ago
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Given the equation below, which of the following shows the quadratic formula
Musya8 [376]

Answer:

Step-by-step explanation:

x=\frac{-(-9)\pm\sqrt{(-9)^2-4(2)(4)} }{2 \times 2} \\x=\frac{9\pm\sqrt{81-32} }{4} \\x=\frac{9\pm\sqrt{49} }{4} \\x=\frac{9 \pm 7}{4} \\either~x=\frac{9+7}{4} =\frac{16}{4} =4\\or\\x=\frac{9-7}{4} =\frac{2}{4} =\frac{1}{2}

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2 years ago
A circle has a sector with area 24/5 pi and central angle of 48 degrees. What is the area of the circle?
Nonamiya [84]

(24/5)π = (48/360) A

(24/5)π = (15/2) A

(24/5)π × (2/15) = A

(8/5)π × (2/5) = A

(16/25)π = A

5 0
3 years ago
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Let A = {−2, −1, 0, 1, 2, 3, 4, 5, 6} and define a relation R on A as follows: For all (m, n) is in A, m R n ⇔ 5|(m2 − n2). It i
anastassius [24]

Answer:

Step-by-step explanation:

find the attached answer below

3 0
3 years ago
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