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Dennis_Churaev [7]
3 years ago
6

PLEASE HELP! will give points, no step by step needed

Mathematics
1 answer:
matrenka [14]3 years ago
7 0

Answer:

the total cost would be $15,900

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Write 314,207 in expanded form
Otrada [13]
314,207                                                                                        300,000+10,000+4,000+200+7 
i hope it work

3 0
2 years ago
Read 2 more answers
Prove that C(50,3) + C(50,4) = C(51,4)
valkas [14]

By definition of the binomial coefficient,

C(n,k) = \dfrac{n!}{k!(n-k)!}

so we have

C(50,3) + C(50,4) = \dfrac{50!}{3!47!} + \dfrac{50!}{4!46!} \\\\ = \dfrac{50!}{3!46!} \left(\dfrac1{47} + \dfrac14\right) \\\\ = \dfrac{50!}{3!46!} \times \dfrac{51}{188} \\\\ = \dfrac{51!}{3!46!} \times \dfrac1{4\times47} \\\\ = \dfrac{51!}{4!47!} \\\\ = \dfrac{51!}{4!(51-4)!} = C(51,4)

as required.

5 0
2 years ago
Complete the following statements.
Ray Of Light [21]
1.
11 16
— X — = 44
4 1

Answer to number 1. —- 44 cups.

2.
880 yards is half of 1,760. So, if 1,760 yards is 1 mile then 880 yards (1/2) is .5 mile.

Answer to number 2. —- 0.5 mile.

3.
36 7
— X — =84
1 3


Answer to number 3. —- 84 inches.



ANSWER:
1. 44 cups
2. 0.5 mile
3.84 inches

Hope this helped you understand you how to do this. Have a great day. A thank you and (or) brainliest is always appreciated. (Optional....) Goodbye!
8 0
3 years ago
You are making cupcakes and the recipe specifies 6 small eggs for every 27 cupcakes. You need to make 36 cupcakes. How many smal
astra-53 [7]
For every egg you can make 4.5 cupcakes so you will need 8 small eggs because 8 times 4.5 equals 36
6 0
3 years ago
Offering 40 points and brainliest for answer
Nata [24]
In fact, this problem belongs to the chemistry section.  Recall that many other sciences require mathematical calculations.  The problem will belong to Mathematics only if no knowledge of other sciences are required to solve the problem.

Solubility for the given substances is measured in grams per 100 g of water at a particular temperature (20 deg.C).
This means that the mass (assumed to be the solute) will not change the solubility, just the minimum quantity of solvent (water) will.
Thus the solubility of sodium chloride will remain L=36 g/100g H2O for any quantity of solute.  Similarly, the solubility of lead nitrate will remain as K=54 g/100 g H2O.

The reason that they remain constant is because the quantity of solvent (water) is fixed at 100 g.  Varying amount of solute will affect the quantity of solvent required, but not the solubility.
I'll leave it to you to calculate the difference between K & L.
8 0
2 years ago
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