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MissTica
2 years ago
5

Write 314,207 in expanded form

Mathematics
2 answers:
Degger [83]2 years ago
8 0
Three hundred and fourteen thousand, two hundred and seven

Or

300000 + 10000 + 4000 + 200 + 7

I'm not sure what one you are looking for so I did both
Otrada [13]2 years ago
3 0
314,207                                                                                        300,000+10,000+4,000+200+7 
i hope it work

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Can some one help me on this
Vilka [71]
28 divided by 4 = 7
so do 7 * 5 which is 35 so they make 35 cookies in 5 seconds
4 0
2 years ago
Find the perimeter of the following shape, round to the nearest tenth
dybincka [34]

Answer: you take the slope of the lines rise over run and add together

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A quantity, y, varies directly as x When y=10, x=6.<br> Find xwhen y= 14.
grigory [225]

The value of x when y = 14 is 8.4

<h3 />

<h3>How to solve variation ?</h3>

y, varies directly as x. Therefore,

y ∝ x

Therefore,

y = kx

where

  • k =constant of proportionality

Therefore,

10 = 6k

k = 10 / 6

k = 5 / 3

Hence, when y = 14

y = kx

14 = 5 / 3 x

cross multiply

42 = 5x

x = 42 / 5

x = 8.4

learn more on variation here: brainly.com/question/20707320

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7 0
2 years ago
Tia owns a fruit shop and is selling a fresh lot of apples and oranges. She wants the ratio of apples to oranges sold to be 3 to
prisoha [69]

i have no idea how many apples should she sell

6 0
3 years ago
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Fifteen SmartCars were randomly selected and the highway mileage of each was noted The analysis yielded a mean of 47 miles per g
laiz [17]

Answer: a. 47 plusminus (1.753*(5 ÷ 3.8730)

Step-by-step explanation:

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

The sample mean, x is the point estimate for the population mean.

Margin of error = z × s/√n

Where

s = sample standard deviation = 5

n = number of samples = 15

z represents the test statistic

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the test statistic score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 15 - 1 = 14

Since confidence level = 90% = 0.90, α = 1 - CL = 1 – 0.90 = 0.1

α/2 = 0.1/2 = 0.05

the area to the right of z0.05 is 0.05 and the area to the left of z0.05 is 1 - 0.05 = 0.95

Looking at the t distribution table,

z = 1.753

Margin of error = 1.753(5 ÷ 3.8730)

Confidence interval = 47 ± 1.753(5 ÷ 3.8730)

8 0
3 years ago
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