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Delvig [45]
3 years ago
5

(-b3 + 3b2 + 8) – ? - 5b2 – 9) = 5b3 +852 +17

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Let's solve for x.

−b3+3b2+8−x−5b2−9=5b3+852+17

Step 1: Add b^3 to both sides.

−b3−2b2−x−1+b3=5b3+869+b3

−2b2−x−1=6b3+869

Step 2: Add 2b^2 to both sides.

−2b2−x−1+2b2=6b3+869+2b2

−x−1=6b3+2b2+869

Step 3: Add 1 to both sides.

−x−1+1=6b3+2b2+869+1

−x=6b3+2b2+870

Step 4: Divide both sides by -1.

−x

−1

=

6b3+2b2+870

−1

x=−6b3−2b2−870

Answer:

x=−6b3−2b2−870

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