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Delvig [45]
3 years ago
5

(-b3 + 3b2 + 8) – ? - 5b2 – 9) = 5b3 +852 +17

Mathematics
1 answer:
ankoles [38]3 years ago
8 0

Let's solve for x.

−b3+3b2+8−x−5b2−9=5b3+852+17

Step 1: Add b^3 to both sides.

−b3−2b2−x−1+b3=5b3+869+b3

−2b2−x−1=6b3+869

Step 2: Add 2b^2 to both sides.

−2b2−x−1+2b2=6b3+869+2b2

−x−1=6b3+2b2+869

Step 3: Add 1 to both sides.

−x−1+1=6b3+2b2+869+1

−x=6b3+2b2+870

Step 4: Divide both sides by -1.

−x

−1

=

6b3+2b2+870

−1

x=−6b3−2b2−870

Answer:

x=−6b3−2b2−870

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The solution of the given equation is:

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<h2>Step-by-step explanation:</h2>

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(y-4)(-4y+16)-(-2y-28)(y-4)=0\\\\i.e.\\\\(y-4)(-4y-16+2y+28)=0\\\\i.e.\\\\(y-4)(-2y+12)=0\\\\i.e.

y-4=0\ or\ -2y+12=0\\\\i.e.\\\\y=4\ or\ 2y=12\\\\i.e.\\\\y=4\ or\ y=6

but y≠ 4

since, the denominator of the term in the left side of the given equality and the second term in the right side of the given equality will be zero and hence, the expression will be not defined.

Hence, the value of y is: 6

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