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KonstantinChe [14]
3 years ago
15

The electoral college system benefits state governments by

Advanced Placement (AP)
1 answer:
Vinil7 [7]3 years ago
6 0
I think A,B,C are correct
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<span>When humanism spread and affected literature, authors and dramatists began writing about </span>a person's worth as a person, his right to freedom, happiness, development and expression of their abilities.
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A stitch in time saves nine. A penny saved is a penny earned. These sentences are... similar in meaning opposite in meaning neit
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Answer:

Neither the same nor the opposite

Explanation:

<em>A stitch in time saves nine</em> is an idiom meaning that it's better to deal with problems right away and spend less time doing that than later when more time is going to be needed.

<em>A penny saved is a penny earned </em>is an idiom meanings that saving money, even little by little, is as useful as earning more.

When we compare these two idioms, we can see that their meanings are neither the same nor the opposite.

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When can a baserunner lead off in softball
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Answer:

The pitcher for the home team allows a lead-off double in the bottom half of the first inning of a Little League (Major) Division softball game. After returning to the pitcher's circle, the pitcher begins her wind-up to the next batter.

Explanation:

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3 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

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Some of the earliest forms of customer service is goods and services would come to you. Peddlers went to houses, doctors did hours calls...etc
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