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3 years ago

Jared is54 inches tall. Kobe is 5'1 tall. Who is taller ? Explain

Mathematics

2 answers:

Strike441 [17]3 years ago

8 0

5'1 means 5 feet 1 inch. And 54 inches is 4'5.
So therefore Kobe is taller.

svetlana [45]3 years ago

4 0

Kobe is taller . There are 12 inches in a foot and since kobe is 5 foot he is 60 inches tall plus 1 more inch since hes 5"1

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Sam drinks water at an incredible rate. She drinks 2 1/5 liters of water every 3/4 of an hour. Sam drinks water at a constant ra

lora16 [44]

Answer:

2.9 litres

2 14/15 litres

Step-by-step explanation:

To determine the amount of water Sam drinks in an hour, divide the total amount drunk by the number of hours

Amount drank in an hour = total litres drunk / time

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7 0

2 years ago

PLEASE HELP

Sergeeva-Olga [200]

Answer:

y = 2

Step-by-step explanation:

I will solve this problem, using the elimination method.

-2(5x - 3y) = -11

-10x + 6y = 22

2x - 6y = -14

Subtract and divide for x

-8x = 8

x = -1

Input -1 into the equations

2(-1) - 6y = -14

-6y - 2 = -14

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y = 2

Thanks!

5 0

3 years ago

What is the slope between the points 5,-1 and -2,-3?

pishuonlain [190]

To find slope, use the equation (y2-y1)/(x2-x1). In your case, the equation is going to look like (-3 - -1)/(5 - -2) or (-3 +1)/(5 + 2), and that simplifies to -2/7.

8 0

4 years ago

A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%

IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

$P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18$

a) P(firm will make at least one hire)

$P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32$

Also,

$P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4$

$\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9$

b) expected value and the standard deviation of the number of hires.

$E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58$

$E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89$