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3 years ago

the lock is numbered from 0 to 49 Each combinations uses 3 numbers in a left and right pattern find the total number

1 answer:

4 0

If ur trying to find how many possible combinations are possible with a lock that has 49 digits.. an there has to be 3 digits in 1 combination then there would be 147 possible combinations

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Write 165% as a decimal and as a mixed number or fraction in spimplest form

PilotLPTM [1.2K]

Answer:

1.65

Step-by-step explanation:

because every percentage is 100

therefore 165/100 = 1.65

4 0

4 years ago

Can someone help me plz

wel

Answer: The correct answer is Choice C.

Step-by-step explanation: The drama club raised 150% of their goal, which is represented by choice c.

The proper way to calculate this percentage is to calculate how much they earned over the goal. They earned $150 over a goal of $300, so you divide 150 by 300 to determine the percentage.

150/300 = .5, or 50%

So, they earned 100% (300) plus 50% (150), for a total of 150% of the goal.

7 0

4 years ago

a woman is expecting triplets. what is the probability that there are 2 girls and 1 boy? what is the probability that all 3 babi

navik [9.2K]

Let the boy be B and the girl be G
there are six possible outcomes
BGG, GBB, GBG, BGB, BBB, and GGG
therefore the probability of getting one boy and two girls is $\frac{1}{6}$
also the probability of getting 3 girls is $\frac{1}{6}$

8 0

4 years ago

Read 2 more answers

A telephone pole has a wire to its top that is anchored to the ground. The distance from the bottom of the pole to the anchor po

Bumek [7]

Answer:

The height of the pole is 105ft,

Step-by-step explanation:

Let us call $h$ the height of the pole, then we know that the distance from the bottom of the pole to the anchor point is 49, or it is $h - 49$ .

The wire length $d$ is 14 ft longer than height $h$ , hence

$d= h+14$ .

Thus we get a right triangle with hypotenuse $d= y+14$ , perpendicular $h$ , and base $h-49$ ; therefore, the Pythagorean theorem gives

$(h-49)^2+h^2 = (h+14)^2$

which upon expanding we get:

$h^2-98h+2401 = h^2+28h+196$

further simplification gives

$h^2-126h+2205=0$ ,

which is a quadratic equation with solutions

$h =21ft\\h = 105ft.$

Since the first solution $h =21ft$ will give the triangle base length of $21ft-49ft = -28ft$ which is negative; therefore, we disregard it and pick the solution $h = 105ft$ .