Given:
The equation of a circle is
A tangent line l to the circle touches the circle at point P(12,5).
To find:
The gradient of the line l.
Solution:
Slope formula: If a line passes through two points, then the slope of the line is
Endpoints of the radius are O(0,0) and P(12,5). So, the slope of radius is
We know that, the radius of a circle is always perpendicular to the tangent at the point of tangency.
Product of slopes of two perpendicular lines is always -1.
Let the slope of tangent line l is m. Then, the product of slopes of line l and radius is -1.
Therefore, the gradient or slope of the tangent line l is 
.
Answer: X=365/83 OR x= 4.39
Step-by-step explanation:
Answer:
Consecutive odd integers are 19 , 21 & 23
Step-by-step explanation:
Let the first 3 consecutive odd intergers be x , (x + 2) and (x + 4).
According to the question,
Eliminating 2x from both the sides,
So, the consecutive odd integers are = 19 , 21 & 23.
0.04 is 1/10 of 0.4
0.4 x 0.10 = 0.04
hope this helps
Answer:
Step-by-step explanation:
Given the definite integral 
, we to evaluate it. Using integration by substitution method.
Let u = 1-2x⁵ ...1
du/dx = -10x⁴
dx = du/-10x⁴.... 2
Substitute equation 1 and 2 into the integral function and evaluate the resulting integral as shown;
![= \dfrac{-1}{10} \int\limits {\dfrac{du}{u^5} } \\\\= \dfrac{-1}{10} \int\limits {{u^{-5}du } \\= \dfrac{-1}{10} [{\frac{u^{-5+1}}{-5+1}] \\\\= \dfrac{-1}{10} ({\frac{u^{-4}}{-4})\\\\](https://tex.z-dn.net/?f=%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5Cint%5Climits%20%7B%5Cdfrac%7Bdu%7D%7Bu%5E5%7D%20%7D%20%20%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5Cint%5Climits%20%7B%7Bu%5E%7B-5%7Ddu%20%7D%20%20%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%5B%7B%5Cfrac%7Bu%5E%7B-5%2B1%7D%7D%7B-5%2B1%7D%5D%20%20%5C%5C%5C%5C%3D%20%5Cdfrac%7B-1%7D%7B10%7D%20%28%7B%5Cfrac%7Bu%5E%7B-4%7D%7D%7B-4%7D%29%5C%5C%5C%5C)
substitute u = 1-2x⁵ into the result
Hence
