Answer:
As per the statement:
Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.
Let H represents Hawick , A represents Abbotsford and K represents Kelso
See the diagram as shown below:
Distance of AH = 15 miles
Distance of AK = 17 miles.
We have to find the distance HK:
Using Pythagoras theorem;
then;
or
miles.
Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles
Answer:
see below
Step-by-step explanation:
3x^2 + 17x +10 =0
(3x+ ) ( x+ ) =0
We need to factor 10 = 2*5 or 1*10
They are positive since we have all positive terms
3*5 = 15+2 = 17
The 5 needs to multiply the 3 so it goes on the outside
(3x+ ) ( x+ 5 ) =0
That leaves the 2 on the inside
(3x+ 2 ) ( x+ 5 ) =0
Using the zero product property
3x+2 =0 x+5=0
3x = -2 x=-5
x = -2/3 x = -5
Answer:
2x*x
2x*-5
1*x
1*-5
2x²-10x+x-10 add numbers that have similar variables
-2x²-10x+x-10
=[-2x²-9x-10]
The rockets rate of change in miles per second is:
(5 - 1)/(2.5*60 - 30) = 1/30 miler per second or 0.033
the rockets rate of change in miles per minute is:
(5 - 1)/(2.5 - 30/60) = 2 miles per minute
Answer:
where is the figure
Step-by-step explanation:
