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asambeis [7]
4 years ago
14

Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places

where appropriate.)
cos(θ) = 1/2
Mathematics
1 answer:
Ghella [55]4 years ago
7 0

Answer:

That is the solutions are:

\frac{\pi}{3}+2\pi \cdot k,\frac{5\pi}{3}+2\pi \cdot k

Step-by-step explanation:

The period of \cos(x) or \sin(x) is 2\pi.

Let's look at the first rotation to see when \cos(\theta)=\frac{1}{2} happens.

This happens at \frac{\pi}{3} and also at \frac{5\pi}{3}. (Notice I just looked at the x-coordinates because that is what cosine is. Sine is the y-coordinate.)

Now to find the rest of the solutions we can just make full rotations either way to get back to those points .

That is the solutions are:

\frac{\pi}{3}+2\pi \cdot k

\frac{5\pi}{3}+2\pi \cdot k

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