From the given tabular data,
Volume of water (V) = 50.0 ml
Mass of water (m) = 49.7 g
So, the density of water (ρ) = Mass / Volume
or, = 49.7 g /50.0 ml = 0.994 g / ml
<u>Actual value of the density of water (ρ') = 0.998 g /ml</u>
So, the percentage error in the density of water
= [( actual value - observed value) / actual value ] ×100
or, = [ (0.998 g /ml - 0.994 g / ml ) / 0.998 g /ml ] ×100
or, = 0.4 %
Hence, the required % error in the density of water will 0.4 %.
Answer:
The answer to your question is 900 black and white copies
Step-by-step explanation:
Data
9 black and white copies for every 2 colored
printed 200 color copies
black and white copies = ?
Process
This is a proportion exercise
BW : C :: bw : c
9 : 2 :: bw : 200
bw = 200(9) / 2
bw = 1800 / 2
bw = 900 copies
The answer is A ∪ B = {2, 4, 5, 6, 8, 10, 12}
A = {2, 4, 6, 8, 10, 12}
B = {5, 10}
A ∪ B. The union of two sets is everything in both sets. So we will combine the outcomes in set A and set B. Since in set B 10 is an even number, we will just add number 5 in <span>A ∪ B.
</span>
A ∪ B = {2, 4, 5, 6, 8, 10, 12}
The acceleration of the fire truck is 1.666 m/s².
<u>Step-by-step explanation:</u>
Acceleration is the measure of change in velocity with respect to time. So as the initial velocity of the fire truck is given as 0 km/hr and the final velocity is given as 66 km/hr. So at first the truck is at rest and on switching on the engine, the truck gets to the velocity of 66 km/hr in 11 seconds.
But first the units of velocity should be changed from km/hr to m/s
1 hour = 3600 seconds
1 km = 1000 m
So, 
Converted Velocity = 18.33 m/s
Then, the acceleration will be
Acceleration = 1.666 m/s²
So, the acceleration of the fire truck is 1.666 m/s².
