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Vladimir [108]
2 years ago
5

OMG yall go to the question ( Whats 4 3/4 times 3 4/5 ) scroll down to my answer and read the chat because people r really tryin

g to online date on here
Mathematics
2 answers:
VashaNatasha [74]2 years ago
6 0

Answer:

bro lol

Step-by-step explanation:

Ahat [919]2 years ago
6 0

where the chats at, im trynna go look lol

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(4 1/3 * (-1) * 5) / 12 = -1.80555556

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kifflom [539]

Answer:

26018.979

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4 0
3 years ago
I need help drawing the graph of -2x+2y=-4
True [87]
Arrange in slope intercept form.....
2y = 2x -4
y = x - 2

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4 0
3 years ago
Read 2 more answers
Explain intersecting, perpendicular, and parallel
inessss [21]
Intersecting is where two lines cross at any angle.
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5 0
3 years ago
Read 2 more answers
Esma and Hunter were trying to solve the equation:
Leni [432]

Answer:

both

Step-by-step explanation:

When would these strategies work?

Esma wants to solve by completing the square. If our equation looks like

a

x

2

+

b

x

+

c

=

k

ax

2

+bx+c=ka, x, squared, plus, b, x, plus, c, equals, k, this strategy would work. If

a

=

1

a=1a, equals, 1, we can square half of

b

bb to find what number completes the square. If

a

>

1

a>1a, is greater than, 1, we need to factor before we complete the square.

Hunter wants to solve using the zero product property. If we have a factored expression that equals zero, this strategy would work.

Whose strategy would work to solve

x

2

+

8

x

=

2

x

−

8

x

2

+8x=2x−8x, squared, plus, 8, x, equals, 2, x, minus, 8?

Hint #22 / 4

Esma's strategy

Esma is correct that adding

1

11 to both sides completes the square. She can factor

x

2

+

6

x

+

9

x

2

+6x+9x, squared, plus, 6, x, plus, 9 and rewrite the equation as

(

x

+

3

)

2

=

1

(x+3)

2

=1left parenthesis, x, plus, 3, right parenthesis, squared, equals, 1. Then she can solve using square roots.

So Esma's strategy would work.

[Show me this strategy worked out.]

Hint #33 / 4

Hunter's strategy

Hunter is correct that he can factor

x

2

+

6

x

+

8

x

2

+6x+8x, squared, plus, 6, x, plus, 8 as

(

x

+

2

)

(

x

+

4

)

(x+2)(x+4)left parenthesis, x, plus, 2, right parenthesis, left parenthesis, x, plus, 4, right parenthesis.

He can then solve

(

x

+

2

)

(

x

+

4

)

=

0

(x+2)(x+4)=0left parenthesis, x, plus, 2, right parenthesis, left parenthesis, x, plus, 4, right parenthesis, equals, 0 using the zero product property since he has a factored expression equal to zero.

So Hunter's strategy would work.

[Show me this strategy worked out.]

Hint #44 / 4

Answer

Both of Esma's and Hunter's strategies would work.

7 0
3 years ago
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