Heather sampled the ages of 50 randomly selected people that frequented a store and obtained a mean of 24. She constructed a 95%
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Solve <span>4x − 3y = 3 and 5x − 4y = 3
Step 1: Solve for x in 4x-3y=3:
4x-3y=3
4x-3y+3y=3+3y [Add 3y to both sides]
4x=3y+3
</span>
[Divide both sides by 4]
x=
Step 2: Substitute
<span> for x in 5x-4y=3
5x-4y=3
5(</span><span>)-4y=3
</span>
[Subtract 
to both sides]
[Divide both sides by 
]
<span>y = 3
Step 3: Substitute 3 for y in x = </span>
x = 3
Step 1: Solve for x in 4x-3y=3:
4x-3y=3
4x-3y+3y=3+3y [Add 3y to both sides]
4x=3y+3
</span>
x=
Step 2: Substitute
5x-4y=3
5(</span>
</span>
<span>y = 3
Step 3: Substitute 3 for y in x = </span>
x = 3