The y int is where the line crosses the y axis ...so ur y int is 3 or (0,3).
ur slope...start at the y int (0,3)....and if u come down 3, and go to the right 2, and down 3, and to the right 2 u are landing on ur line. So ur slope is -3/2
Answer:
1 : 4
Step-by-step explanation:
Remember, your units have to match, so
3 in : 1 ft
doesn't look right, change 1 ft to 12 in.
3 in : 12 in
reduce by 3
1 : 4
Think of it as (-4x+1)(3x+2) then distribute: -4x x 3x= -12x^2, -4x x 2= -8x, 1 x 3x = 3x, and 2 x 1=2. put together all the answers we just got so: -12x^2 - 8x +3x +2 then simplify to get -12x^2 -5x +2
Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
Answer:
2y+12
Hope this helps
Step-by-step explanation:
