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klasskru [66]
2 years ago
5

Complete this statement 24x^4a^2+30x^2a^3=6x^2a^2 ( )

Mathematics
1 answer:
Molodets [167]2 years ago
8 0
<span>24x</span>⁴<span>a</span>² <span>+ 30x</span>²<span>a</span>³ <span>= 6x</span>²<span>a</span>²<span>(4x</span>² + 5a<span>)</span>
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3 years ago
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A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o
kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

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(2400+2w^2)/w =150

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Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0
3 years ago
Help, guys I have NO CLUE how to do this
Nikitich [7]
Subtract c and then x = y - c

And that's it!
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3 years ago
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<img src="https://tex.z-dn.net/?f=2x2%20-%2054%20%2B%2059" id="TexFormula1" title="2x2 - 54 + 59" alt="2x2 - 54 + 59" align="abs
Westkost [7]
The answer should be 4x+5

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2 years ago
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For the entire scatter plot is the association between the year and the distance jumped linear or nonlinear
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your stupid........................................................................

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