Answer:
Step-by-step explanation:
Correct option is
D
[1,(1+π)
2
]
f(x)=(1+sec
−1
(x))(1+cos
−1
(x))
Here the limiting component is cos
−1
(x), since the domain of cos
−1
(x) is [−1,1].
Therefore,
f(1)=(1+0)(1+0)
=1
f(−1)=(1+π)(1+π)
=(1+π)
2
Hence range of f(x)=[1,(1+π)
2
]
Answer:
D. 
Step-by-step explanation:
The graph of f^-1 (x) is
called the inverse function of f (x). The relationship between the two is that the
point (x,y) is on the graph of f (x) if and only if the point (y,x) is on the
graph of f^-1 (x).
This means that if the point
(2, 7) is on f (x), therefore the point (7, 2) is on f^-1 (x).
<span>Answer: (7, 2)</span>
11. Assuming distance is proportional to time,
.. (3 h)/(7 h) = d/(665 km)
.. d = (665 km)*(3/7) = 285 km . . . . . . selection B
12. (30 L)/(1.5 L/min) = 20 min . . . . . . selection C
