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Soloha48 [4]
3 years ago
10

The digits of a two-digit number sum to 8. When the digits are reversed the resulting number is 18 less than the onginal

Mathematics
1 answer:
polet [3.4K]3 years ago
7 0

Answer:

53

Step-by-step explanation:

Given: The sum of two digit number is 8

           Reversing the digit will get us number 18 less than the original.

Lets take x as tenth digit of our number and y as unit digit of our number.

As given sum of digit is 8

∴ x+y= 8

∴ y= 8-x -       equation 1

We also know that reversing the digit will get us number 18 less than the original.

∴ 10y+x = 10x +y-18

Now, lets put the value of y from equation 1

⇒ 10(8-x) + x = 10x+ (8-x)- 18

⇒ 80-9x= 9x-10

⇒ 90= 18x

∴ x= 5

Next, substituting the value of x in equation 1

y= 8-x

⇒ y= 8-5 = 3

∴ y= 3

∴ The original number is 53, sum of the digit is 8 and if we reverse the digit of the number, we get 35, which is 18 less than the original number.

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Step-by-step explanation:

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