The ratio of the difference of the two means to Sidney’s mean absolute deviation is; 4/3.28
<h3>How to find the Mean Absolute Deviation?</h3>
From the given table, we see that;
Mean grade of Sidney = 82
Mean grade of Phil = 78.
Mean absolute deviation of Sidney = 3.28
Mean absolute deviation of Phil = 3.96.
The difference between the two means of Sidney and Phil = 82 - 78 = 4.
Thus, the ratio of the difference of the two means to Sidney’s mean absolute deviation is; 4/3.28
Complete Question is;
The means and mean absolute deviations of Sidney’s and Phil’s grades are shown in the table below. Means and Mean Absolute Deviations of Sidney’s and Phil’s Grades Sidney Phil Mean 82 78 Mean Absolute Deviation 3.28 3.96 Which expression represents the ratio of the difference of the two means to Sidney’s mean absolute deviation?
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Answer:
C. opposite sides are parelell
Plug in (-1, 3) into both equations
Ax - 2y = 4
A(-1) - 2(3) = 4
-A - 6 = 4 Add 6 on both sides
-A = 10 Divide -1 on both sides
A = -10
5x + By = -1
5(-1) + B(3) = -1
-5 + 3B = -1 Add 5 on both sides
3B = 4 Divide 3 on both side
B =
The slope of the line would be m = 1/4