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Sonja [21]
3 years ago
6

PLEASE HELP WITH GEOMETRY!! WILL GIVE BRAIN!!!

Mathematics
2 answers:
xenn [34]3 years ago
5 0

Answer:

1,726 cm

Step-by-step explanation:

it boils down to this equation:

2(19×29)+2(19×6.4)+2(29×6.5)

bc if you look closely, it's just each side twice (hope that makes sense)

then you work down from there

2(551)+2(123.5)+2(188.5)

1,102+259+337

1,726

Sonbull [250]3 years ago
5 0

Answer:

L = 19

B = 6.5

H = 29

surface \ area = 2 ((L\times B) + (B \times H) + (H \times L))

                    =2((19\times 6.5) +(6.5 \times 29) + (29\times 19)) \\\\= 1726cm^2

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Assuming equal rates, 120 miles in 4 hours implies 225 miles in how many hours?
nata0808 [166]

Answer:

7.5 hours

Step-by-step explanation:

Step 1:

120/4 = 225/x       Equation

Step 2:

120x = 900

Step 3:

x = 900 ÷ 120           Divide

Answer:

x = 7.5

Hope This Helps :)

3 0
3 years ago
HELP AND NO LINKS HELP
nignag [31]

Answer:

b.

Step-by-step explanation:

Each of the provided angles are also a part of linear pairs, so 180-145=35

180-100=80

35+80=115

To solve for the final angle/the one they are wanting

180-115=65

4 0
3 years ago
Can y’all help me on question 33?!
solniwko [45]
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3 years ago
The McLean family drove 302.5 miles in 5.5 hours. How many miles could they drive at this rate in 4 hours?
Margaret [11]
The McLean family could drive 220 miles in four hours.
7 0
4 years ago
Multiple-Choice Integration, Picture Included, Please Include Work
ValentinkaMS [17]
\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx

Recall that a circle of radius 2 centered at the origin has equation

x^2+y^2=4\implies y=\pm\sqrt{4-x^2}

where the positive root gives the top half of the circle in the x-y plane. The definite integral corresponds to the area of the right half of this top half. Since the area of a circle with radius r is \pi r^2, it follows that the area of a quarter-circle would be \dfrac{\pi r^2}4.

You have r=2, so the definite integral is equal to \dfrac{2^2\pi}4=\pi.

Another way to verify this is to actually compute the integral. Let x=2\sin u, so that \mathrm dx=2\cos u\,\mathrm du. Now

\displaystyle\int_0^2\sqrt{4-x^2}\,\mathrm dx=\int_0^{\pi/2}\sqrt{4-(2\sin u)^2}(2\cos u)\,\mathrm du=4\int_0^{\pi/2}\cos^2u\,\mathrm du

Recall the half-angle identity for cosine:

\cos^2u=\dfrac{1+\cos2u}2

This means the integral is equivalent to

\displaystyle2\int_0^{\pi/2}(1+\cos 2u)\,\mathrm du=2u+\sin2u\bigg|_{u=0}^{u=\pi/2}=\pi
4 0
3 years ago
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