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Masja [62]
4 years ago
12

In the figure below, which term best describes point T?

Mathematics
1 answer:
chubhunter [2.5K]4 years ago
3 0

Answer:

A

Step-by-step explanation:

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ΔABC has coordinates A(8, −4), B(2, 2), and C(0, −6). Write the coordinates of the image after a dilation with a scale factor of
MakcuM [25]

Answer:

formula= (kx,ky)

where k = scale factor

= A((8,-4)

= A= (8×12,-4×12)

<u>A= (96,-48)</u>

B= (2,2)

= (2×12,2×12)

<u>B= (24,24)</u>

C= (0,-6)

= (0×12,-6×12)

<u>C= (0,-72)</u>

4 0
3 years ago
Find the 9th term of the geometric sequence 5, -25, 125
UkoKoshka [18]

Answer:

The previous number keeps getting multiplied by - 5

Step-by-step explanation:

5 × -5 = -25

-25 × -5 = 125

125× -5 = -625

-625 × -5 = 3,125

3125 × -5 = -15,625

-15,625 × -5 = 78,125

78,125 × -5 = -390, 625

-390,625 × -5 = 1,953,125

1,953,125 × -5 = 9,765,625

:)

7 0
3 years ago
A waitress works 1.75 hours less in the afternoon than in the evening. If she works 5      1/8
gayaneshka [121]
Let x be the number of hours that the waitress works in the evening.

We know for our problem that she works 5 \frac{1}{8} in the afternoon and that she works <span>1.75 hours less in the afternoon than in the evening, so:
</span>x=5 \frac{1}{8} -1.75
<span>Since </span>\frac{1}{8} =0.125, we can rewrite our expression:
x=5.125-1.75
x=3.375

We can conclude that she works 3.375 hours in the evening, or expressed as a mixed fraction: 3 \frac{3}{8} hours.
3 0
4 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
3 years ago
Simplify each expression using order of operations. (the one that’s circled)
Zepler [3.9K]

Answer:

18

Step-by-step explanation:

1. 6x6=36

2. 8+36=44

3. 44/11=4

4. 7x2=14

5. 4+14=18

5 0
3 years ago
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