so I think 37\12 is the answer to this question
Answer:
option B is correct -7 is the answer
Step-by-step explanation:
=4⁴-3³.(12-3)-20
=256-27×(9)-20
=256-243-20
=256-263
=-7
hope it will help ^_^
Answer:
The value of Car B will become greater than the value of car A during the fifth year.
Step-by-step explanation:
Note: See the attached excel file for calculation of beginning and ending values of Cars A and B.
In the attached excel file, the following are used:
Annual Depreciation expense of Car A = Initial value of Car A * Depreciates rate of Car A = 30,000 * 20% = 6,000
Annual Depreciation expense of Car B from Year 1 to Year 6 = Initial value of Car B * Depreciates rate of Car B = 20,000 * 15% = 3,000
Annual Depreciation expense of Car B in Year 7 = Beginning value of Car B in Year 7 = 2,000
Conclusion
Since the 8,000 Beginning value of Car B in Year 5 is greater than the 6,000 Beginning value of Car A in Year 5, it therefore implies that the value Car B becomes greater than the value of car A during the fifth year.
3y=8x
Explanation:
If y varies directly with x then
y=c⋅x for some constant of variation c
If (x,y)=(14,23) is a solution to this equation, then
23=c⋅14
→c=23⋅41=83
So
y=83x
or (clearing the fraction)
3y=8x
