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3 years ago

Mary and Julie both have a goal of raising $1000 for charity. Mary raises $12 every 4 days. Julie raises $19 every 6 days.

Mathematics

2 answers:

zvonat [6]3 years ago

6 0

Answer:

juile

Step-by-step explanation:

BARSIC [14]3 years ago

3 0

No idkdjkdkdksjdkkdjjdkcklddfosodjodpdoc

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Solve for the value of r. (8r+6)° (9r-7)

lukranit [14]

Answer:

r = 13

Step-by-step explanation:

these angles are vertical and are congruent

8r + 6 = 9r - 7

6 = r - 7

13 = r

8 0

2 years ago

Pleases help quick please

Solnce55 [7]

Answer:

1 and 2

Step-by-step explanation:

$\sqrt{2}$ = 1.41421356237

3 0

3 years ago

Read 2 more answers

Factor completely 4h2 + g.

stiv31 [10]

Answer:

8h + g

Step-by-step explanation

When you say "4h2", do you mean 4h multiplied by 2?

If so, then 4h2 = 8h, and 8h+g would be your answer.

Hope this helps :)

8 0

2 years ago

Read 2 more answers

The shoe store has twice as many black shoes as it does brown shoes. The total number of shoes is 66. How many brown shoes are t

fredd [130]

<span>x=number of brown shoes
2x=number of black shoes (twice as many black shoes as brown shoes)
so x+2x=66
add like terms 3x=66
solve for x by dividing 3; x=22
so there are 22 brown shoes and 44 black shoes (2 x 22= 44)</span>

5 0

3 years ago

For the function given state the period f(t) =6sin(3t-pi/6)-1

lapo4ka [179]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}}
\\\\
f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\
f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}}

\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{ A}}|\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\qquad \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\qquad \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)
\end{array}$

now, with that template in mind, let's take a peek at yours

$\bf \begin{array}{lllcclll}
f(t)=&6sin(&3t&-\frac{\pi }{6})&-1\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
period\qquad \cfrac{2\pi }{B}\iff\cfrac{2\pi }{3}$

8 0

3 years ago