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3 years ago

Please answer this in two minutes

Mathematics

1 answer:

BartSMP [9]3 years ago

6 0

Answer: 43.25?

Step-by-step explanation:

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Show that 7x + 1 is equivalence to 2(2x - 1) + 3(x + 1)

marissa [1.9K]

7x + 1 = 2(2x - 1) + 3(x + 1)

7x + 1 = 4x - 2 + 3x + 3

7x + 1 = 7x + 1

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1 year ago

Read 2 more answers

Using the 10% value to find 20% of 300

neonofarm [45]

20% * 300 = 2 * (10% * 300) = 2*30 = 60

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3 years ago

Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your

Darina [25.2K]

Answer:

Given definite integral as a limit of Riemann sums is:

$\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Step-by-step explanation:

Given definite integral is:

$\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}$

Substituting (2) in above

$f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

Riemann sum is:

$= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]$

4 0

3 years ago

PLEASE HELP!!!

NemiM [27]

Answer:

D. 2 3 • 3 2 • 5

Step-by-step explanation:

ig I need at least 20 characters to submit my answer. :)

8 0

3 years ago

LCM of 294 and 1260<br><br>

Alex Ar [27]

Answer:

8820

Step-by-step explanation:

Prime factorization of 294,

→ 2 × 3 × 7 × 7

Prime factorization of 1260,

→ 2 × 2 × 3 × 3 × 5 × 7

LCM of 294 and 1260,

→ 2 × 2 × 3 × 3 × 5 × 7 × 7

→ 8820

Hence, the LCM is 8820.

4 0

1 year ago