If f(x) = 3x -2 and g(x).= 4x + 1.<br> what is the sum of f(2) and g(-3)

Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

3 years ago

John needs 2.50. He has 0.75. How much more money does he need

NeTakaya

If John has $0.75 and he needs $2.50, then you will subtract $0.75 from $2.50 to find out how much he needs which is $1.75. Hope I helped! Don't forget to help me with the Brainliest Answer! :D

5 0

2 years ago

Read 2 more answers

What value is equivalent to 108-8x(5-2)-60

emmasim [6.3K]

Answer:

-28 + -1 = -29

-14 + -2 = -16

-7 + -4 = -11

-4 + -7 = -11

-2 + -14 = -16

-1 + -28 = -29

1 + 28 = 29

2 + 14 = 16

4 + 7 = 11

7 + 4 = 11

14 + 2 = 16

28 + 1 = 29

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

1. Find the volume of a cone with a height of 4.8 m and a diameter of 8.4 m.

andrey2020 [161]

Answer:

no

Step-by-step explanation:

ok

3 0

2 years ago

Need help ASAP. i forgot all the steps after the Area is solved with 5. or if 25pi is the right answer.

maxonik [38]

Answer:

$42.5\:\mathrm{m^2}$

Step-by-step explanation:

The area of a sector with measure $\theta$ in degrees is given by $r^2\pi\cdot\frac{\theta}{360}$ , where $r$ is the radius of the sector.

What we're given:

$r$ of 5
$\theta$ of $195^{\circ}$

Solving, we get:

$A_{sector}=5^2\pi\cdot \frac{195}{360}=13.5416666667\pi=42.5424005174\approx \boxed{42.5\:\mathrm{m^2}}$

*Notes:

units should be in square meters (area)
the problem does not say whether to round or leave answers in term of pi, so you may need to adjust the answer depending on what your teacher specifically wants

7 0

2 years ago

If f(x) = 3x -2 and g(x).= 4x + 1. what is the sum of f(2) and g(-3)