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Bezzdna [24]
3 years ago
8

4x=124 what is the solution to this equation?

Mathematics
2 answers:
TEA [102]3 years ago
6 0
X=31 is the answer. you divide both by 4x which the left side will cancel out and be just x and then you divide 124/4 and your answer will be 31.
Fynjy0 [20]3 years ago
5 0
124 / 4 = 31. 

31 would be your the solution of x.
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Brady has collected the following data. 11, 15, 15, h, 11. If the range of Brady's data is 9, what is the value of h?
tankabanditka [31]
To find the value of h, you will order the data and then determine if there is enough information to find the missing value knowing that from the beginning of the data to the end is a range of 9.

11, 11, 15, 15, ____ (20)

or

(6)_____, 11, 11, 15, 15

The missing value of h could be 9 or 20.
8 0
3 years ago
Verify the identitiy:
Advocard [28]

Answer:

\frac{sinx}{1-cos x}     =         cosecx  +  cot x

Step-by-step explanation:

To verify the identity:

sinx/1-cosx = cscx + cotx

we will follow the steps below;

We will take just the left-hand side and work it out to see if it is equal to the right-hand side

sinx/1-cosx

Multiply the numerator and denominator by 1 + cosx

That is;

\frac{sinx}{1-cos x}     =    \frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}

open the parenthesis on the right-hand side of the equation at the numerator and the denominator

sinx(1+cosx) = sinx + sinx cosx

(1-cosx)(1+cosx) = 1 - cos²x

Hence

\frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}     =  \frac{sinx + sinx cosx}{1-cos^{2}x }

But 1- cos²x  = sin²x

Hence we will replace  1- cos²x  by  sin²x

   \frac{sinx}{1-cos x}    =       \frac{sinx(1+cosx)}{(1-cosx)(1+cosx)}     =  \frac{sinx + sinx cosx}{1-cos^{2}x }   =  \frac{sinx+sinxcosx}{sin^{2}x }

                             

                                  =\frac{sinx}{sin^{2}x }   +   \frac{sinxcosx}{sin^{2}x }

                                   

                                   =\frac{1}{sinx}   +   \frac{cosx}{sinx}

             

                                   =cosecx  +  cot x

\frac{sinx}{1-cos x}     =         cosecx  +  cot x

Note that;

\frac{1}{sinx}  = cosecx                        

         

 \frac{cosx}{sinx}   =       cot x

                                     

6 0
3 years ago
What is the correct answer?
Tasya [4]

Given:

The function is

f(x)=(x+3)^2(x-5)^6

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}       ...(i)

where, a is a constant, c_1,c_2,...,c_n are zeros of respective multiplicities m_1,m_2,...,m_n.

We have,

f(x)=(x+3)^2(x-5)^6

On comparing this with (i), we get

c_1=-3,m_1=2

c_2=5,m_2=6

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

5 0
3 years ago
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Liula [17]
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step 2: subtract 30 from both sides
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7 0
3 years ago
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jasenka [17]

Answer:

2:3 (2 bikes for every 3 people)

Step-by-step explanation:

hope this helps

8 0
2 years ago
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