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yuradex [85]
3 years ago
15

In a certain pond, 50 fish were caught, tagged, and returned to the pond. A few days later, 50 fish were caught again, of which

2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what is the approximate number of fish in the pond?(A) 400(B) 625(C) 1,250(D) 2,500(E) 10,000
Mathematics
1 answer:
mario62 [17]3 years ago
6 0

2 out of 50 were tagged.

Divide 2 by 50:

2/50 = 0.4 ( This is 4% of the fish were tagged).

Now divide the number of fish caught by the percentage that were tagged:

50 / 0.04 = 1250

The number of fish in the pond is C. 1250

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Lucas' mom is eight years older than twice his age. The sum of their ages is 77. How old are Lucas and his mom?
Rudiy27

Answer:

Age of Lucas = 23 years

Age of Lucas Mom = 54 Years

Step-by-step explanation:

In this question we have to find the age of Lucas and his Mom

Let the age of Lucas be x

According to given condition

Twice of his age 2 * x =2x

Eight years older means age + 8x

So

Age of his mom = Twice of his age + 8

                           = 2x + 8               .................(ii)

now according to second condition

Age of Lucas + Age of his mom = 77

Put the values in the condition above

x + (2x + 8) = 77

x + 2x + 8 =77

3x + 8 = 77

subtracting 8 from both sides

3x + 8 - 8 = 77 -8

3x = 69

Dividing both sides by 3

x = 69 / 3

x = 23 years

Age of Lucas = 23 years

Now from equation (i)

Age of Lucas Mom = 2(x) + 8

putting in the value we get

Age of Lucas Mom = 2 ( 23) + 8

                               =46 + 8

                               =54 Years

Age of Lucas Mom = 54 Years

3 0
3 years ago
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