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Solnce55 [7]
3 years ago
15

How do I answer this

Mathematics
1 answer:
iris [78.8K]3 years ago
6 0
I don’t know what the answer is to this but if you download Photomath and scan the answer with your phone it will probably give the answer and how to do it
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​△BCD ​ is a right triangle. The length of the hypotenuse is 18 centimeters. The length of one of the legs is 14 centimeters. Wh
belka [17]

In a right triangle, this formula can be used:


a^2 + b^2 = c^2


when a and b are the legs and c is the hypotenuse.


Substitute the numbers from the problem into the formula.


14^2 + b^2 = 18^2


Simplify.


196 + b^2 = 324

b^2 = 128

b = square root of 128 = 11.3137...


When 11.313 is rounded to the nearest tenth, it is 11.3


The length of the other leg is 11.3 centimeters.


Hope this helps!


6 0
3 years ago
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Please help if you want brianleist!! :) uhm don't mind update- NO LINkS child..
Katen [24]

Answer:

5/8

Step-by-step explanation:

total is 16

and point is on 10th line

therefore 10/16 is equals to 5/8

8 0
3 years ago
Read 2 more answers
Please help it would be appreciated
scoray [572]

Answer:

81 in^2

Step-by-step explanation:

Well the formula to find an area of a triangle is (bh) / 2

In this case the base is 18 and the height is 9

18*9=162

162/2=81

5 0
2 years ago
Read 2 more answers
Marcy is taking part in a summer movie club. She will earn 3 points for each movie she attends throughout the summer. Which equa
lawyer [7]
The answer is a \large y=3x
5 0
3 years ago
Write the equation of a quadratic function who has the vertex of (4,-7)
timama [110]

Given:

The vertex of a quadratic function is (4,-7).

To find:

The equation of the quadratic function.

Solution:

The vertex form of a quadratic function is:

y=a(x-h)^2+k          ...(i)

Where a is a constant and (h,k) is vertex.

The vertex is at point (4,-7).

Putting h=4 and k=-7 in (i), we get

y=a(x-4)^2+(-7)

y=a(x-4)^2-7

The required equation of the quadratic function is y=a(x-4)^2-7 where, a is a constant.

Putting a=1, we get

y=(1)(x-4)^2-7

y=(x^2-8x+16)-7             [\because (a-b)^2=a^2-2ab+b^2]

y=x^2-8x+9

Therefore, the required quadratic function is y=x^2-8x+9.

6 0
2 years ago
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