Answer: Vertex = (2, -15) 2nd point = (0, -3)
<u>Step-by-step explanation:</u>
g(x) = 3x² - 12x - 3
= 3(x² - 4x - 1)
a=1 b=-4 c=-1
Find the x-value of the vertex by using the formula for the axis of symmetry: 


= 2
Find the y-value of the vertex by plugging the x-value (above) into the given equation: g(x) = 3x² - 12x - 3
g(2) = 3(2)² - 12(2) - 3
= 12 - 24 - 3
= -15
So, the vertex is (2, -15) ← PLOT THIS COORDINATE
Now, choose a different x-value. Plug it into the equation and solve for y. <em>I chose x = 0</em>
g(0) = 3(0)² - 12(0) - 3
= 0 - 0 - 3
= -3
So, an additional point is (0, -3) ← PLOT THIS COORDINATE
Answer:
Step-by-step explanation:
Polynomial f(x) has the following conditions: zeros of -4 (multiplicity 3), 1 (multiplicity 1), and with f(0) = 320.
The first part zeros of -4 means (x+4) and multiplicity 3 means (x+4)^3.
The second part zeros of 1 means (x-1) and multiplicity 1 means (x-1).
The third part f(0) = 320 means substituting x=0 into (x+4)^3*(x-1)*k =320
(0+4)^3*(0-1)*k = 320
-64k = 320
k = -5
Combining all three conditions, f(x)
= -5(x+4)^3*(x-1)
= -5(x^3 + 3*4*x^2 + 3*4*4*x + 4^3)(x-1)
= -5(x^4 + 12x^3 + 48x^2 + 64x - x^3 - 12x^2 - 48x - 64)
= -5(x^4 + 11x^3 + 36x^2 + 16x -64)
= -5x^3 -55x^3 - 180x^2 - 80x + 320
Answer:
The median, because the data distribution is skewed to the right
Step-by-step explanation:
If the longer part of the box is to the right (or above) the median, the data is said to be skewed right. If the longer part is to the left (or below) the median, the data is skewed left. The data is skewed right. The median would be a better estimate, because one or two numbers on the high end will cause the numbers to be skewed to the right, and the mean to be high
Answer:
12 divided by 48
Step-by-step explanation:
12 divided by 48 is 4 so u need to divide and she what you get and then
that answer and multiply it by 4 and see if you got the same answer and if you did then it is correct unless you have worked it wrong always try your best and work hard
Answer:
1/6
Step-by-step explanation: