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4 years ago

Guys pls help me! ASAP!

Mathematics

1 answer:

Makovka662 [10]4 years ago

4 0

Answer:

Step-by-step explanation:

2. area of a triangle is 1/2 b h

1/2 (5 * 2) = 5 yd squared

area of the circle is pi r squared

you only need 1/2 of this area

find all these areas and add them together.

6. this is just a square sitting on a rectangle.

36 x 36 for the square

36 x 60 for the rectangle

add these together.

8. this a 1/2 circle and a triangle.

area of a circle is pi r squared

r is 7 in this problem

the area of a triangle is 1/2 b h

height is 7x2 here or 14

add the two together.

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A cafeteria worker knows that it takes 3 bottles of juice to serve

marin [14]

Number of bottles of juice are needed for 24 students = 4

Number of bottles of juice are needed for 42 students = 7

<h3><u>Solution:</u></h3>

Given that cafeteria worker knows that it takes 3 bottles of juice to serve a table of 18 students

1) Number of bottles of juice are needed for 24 students

2) Number of bottles of juice are needed for 42 students

Since its given that 3 bottles of juice to serve a table of 18 students

So, number of bottles required for one student is given as:

Let "a" be the number of bottles required for one student

18 students ⇒ 3 bottles

1 student ⇒ "a" bottles

On cross multiplication we get,

$18 \times a = 3 \times 1\\\\a = \frac{3}{18} = \frac{1}{6}$

<h3><em><u>Finding number of bottles of juice are needed for 24 students:</u></em></h3>

number of bottles of juice are needed for 24 students = 24 x number of bottle required for 1 student

$\text {number of bottles of juice are needed for 24 students }=24 \times \frac{1}{6}=4$

<h3><em><u>Finding number of bottles of juice are needed for 42 students:</u></em></h3>

number of bottles of juice are needed for 42 students = 42 x number of bottle required for 1 student

$\text {number of bottles of juice are needed for 42 students }=42 \times \frac{1}{6}=7$

3 0

4 years ago

Y+3/5<br><img src="https://tex.z-dn.net/?f=%20%5Cgeqslant%20" id="TexFormula1" title=" \geqslant " alt=" \geqslant " align="absm

kodGreya [7K]

Y+2/3 -2 y+3/5 what do u want?

3 0

3 years ago

State the complement of each of the following sets: (a) Engineers with less than 36 months of full-time employment. (b) Samples

iren2701 [21]

Answer:

(a) Engineers with greater than 36 months of full-time employment.

(b) Samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter

(d) Cholesterol levels that measure less than 180 and greater than 220.

Step-by-step explanation:

The complement of a set refers to elements that does not exist in that set. It means what does not exist in the set but exist in the universal set.

(a) Engineers with greater than 36 months of full-time employment.

In this case, the Universal set is a set of engineers in full-time employment. The given set is for engineers with less than 36 months of full-time employment. The complement is engineers with greater than 36 months of full-time employment.

(b) Samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter

In this case, the universal set is a set of samples of cement block having compressive strength. The given set is a set of cement block having compressive strength less than 6000 kilograms per square centimeter. The complement is samples of cement blocks with compressive strength greater than 6000 kilograms per square centimeter.

In this case, the universal set is a set of measurements of the diameter of forged pistons. The given set is a set of measurements of the diameter of forged pistons that do not conform to engineering specifications. The complement is a set of measurements of the diameter of forged pistons that conforms to engineering specification.

(d) Cholesterol levels that measure less than 180 and greater than 220.

In this case, the universal set is a set of Cholesterol levels. The given set is Cholesterol levels that measure greater than 180 and less than 220. The complement is Cholesterol levels that measure less than 180 and greater than 220.

5 0

3 years ago

In △QRS, line QR≅line SQ and m∠Q=114∘. find m∠S

JulsSmile [24]

Answer:

prove that lines AK and AL divide BC into three equal parts. 1.30. Point O is the center of the circle inscribed in △ABC. On sides AC and BC points M and K, ...

Step-by-step explanation:

6 0

3 years ago

Find the LCD of the pair of expressions.

Lisa [10]

The correct answer is D.

The LCD, least common denominator, is the smallest denominator that both denominators will go into. The LCD of 5 and 7 will be 35; the variable portion will be b³c, since that is the smallest thing the second fraction can go into.

This gives us a denominator of 35b³c.

6 0

3 years ago