1. 4g= 37-5
⇒ 4g= 32
⇒ g= 32/4
⇒ g= 8
2. c= 5*6
⇒ c= 30
3. f+4= 3*5
⇒f+4= 15
⇒ f= 15-4
⇒ f= 11.
4. b+6= 30/5
⇒ b+6= 6
⇒ b= 6-6
⇒ b=0
5. a-5= 60/5
⇒ a-5= 12
⇒ a= 12+5
⇒ a= 17
6. e+2= 45/5
⇒ e+2= 9
⇒ e= 9-2
⇒ e= 7
7. d-5= 12/3
⇒ d-5= 4
⇒ d= 4+5
⇒ d= 9
8. m-4= 16/4
⇒ m-4= 4
⇒ m= 4+4
⇒ m= 8
9. q+6= 30/5
⇒ q+6= 6
⇒ q= 6-6
⇒ q= 0
10. h/3= 3+5
⇒ h/3= 8
⇒ h= 8*3
⇒ h= 24
11. 3c= 3-5
⇒ 3c= -2
⇒ c= -2/3
12. x/3= 6-7
⇒ x/3= -1
⇒ x= -1*3
⇒ x= -3
13. 6p= 2+1
⇒ 6p= 3
⇒ p= 3/6
⇒ p= 1/2
14. 2d-7= 27/3
⇒ 2d-7= 9
⇒ 2d= 9+7
⇒ 2d= 16
⇒ d= 16/2
⇒ d=8
15. b-3= 5/2
⇒ b-3= 2.5
⇒ b= 2.5+3
⇒ b= 5.5
16. y-1= 1/3
⇒ y= 1/3+1
⇒ y= 1 1/3
17. 5v= 9-3
⇒ 5v= 6
⇒ v= 6/5
⇒ v= 1.2
18. n-3 = 3*6
⇒ n-3= 18
⇒ n= 18+3
⇒ n= 21
19. t+10= 1*4
⇒ t+10= 4
⇒ t= 4-10
⇒ t= -6
20. 3c+4= 3*5
⇒ 3c+4= 15
⇒ 3c= 15-4
⇒ 3c= 11
⇒ c= 11/3
⇒ c= 3 2/3
Hope this helps~
Answer:
scale factor is 2.5
Step-by-step explanation:
Notice that the original image is smaller than the scale drawing. Examine the ratios of the sizes:
Image/ Original :
height: 3.75 in / 1.5 in = 2.5
length: 5 in / 2 in = 2.5
The scale factor is clearly 2.5
Answer:
They spend = $58
They earned = $35
Step-by-step explanation:
First join the log4 on the left:
log4( x*(x-3) = log4(-7x+21)
Then x = -7, works: -7*(-10)=70 = -7*(-7)+21
x=-3, 18 = 42, does not work
x=3 0=0 works,
However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.
Now x=3 gives log4(0) on the left and right, which does not exist.
So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
Answer:
Step-by-step explanation:
h = -5t^2 - 6t + 44
I'll assume 0 meters is the ground height. That would mean we want to know the time, t, for h to be = 0 meters:
h = -5t^2 - 6t + 44
0 = -5t^2 - 6t + 44
5t^2 + 6t -44 = 0
Solve using the quadratic equation: 2.43 and - 3.63 seconds. We'll use the positive value: 2.43 seconds for the ball to reach the ground. Save the -3.63 value for the Klingons.
We can also solve by graphing the function, as per the attached image. Note that the starting time of 0 seconds, the ball is at 44 feet. It reaches the x axis at 2.43 seconds (where x = 0, the ground).
