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3 years ago

Guys pls help me! ASAP!

Mathematics

1 answer:

Makovka662 [10]3 years ago

4 0

Answer:

Step-by-step explanation:

2. area of a triangle is 1/2 b h

1/2 (5 * 2) = 5 yd squared

area of the circle is pi r squared

you only need 1/2 of this area

find all these areas and add them together.

6. this is just a square sitting on a rectangle.

36 x 36 for the square

36 x 60 for the rectangle

add these together.

8. this a 1/2 circle and a triangle.

area of a circle is pi r squared

r is 7 in this problem

the area of a triangle is 1/2 b h

height is 7x2 here or 14

add the two together.

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The quantity, Q, of a drug in the blood stream begins with 250 mg and decays to one-fifth its value over every 90 minute period.

Mazyrski [523]

Answer:

$a=250 \, mg\\\\b=5\\\\T= 90'$

Step-by-step explanation:

We have that $Q(t) = a\cdot b^{-\frac{t}{T}} \\$

Where t is the time (in minutes) and for the sake of dimensional consistency, let's assume that T is also in minutes, b is an adimensional number, and a is in mg. So we will have Q in mg as a consequence.

We now want to find out what values these constants might take. Let's see what happens when $t=0$ , that is, just as we start. At that point, we have that the amount of drug in the bloodstream must be equal to 250mg, thus:

$Q(0)= a\cdot b ^{-\frac{0}{T} }=250\,mg\\Q(0)= a=250\,mg$

We have found the constant $a$ ! It is the initial amount of drug! we have made use of the fact that any number raised to the 0th power is equal to one.

Now, we know that every 90 minutes, the amount of drug decreases to one fifth of its former value. How do we put this in mathematical form? Like so:

$Q(t+90')=Q(t)/5$

That is, 90 minutes after time t the amount of drug will be one fifth of the amount of drug at time t. Let's expand the last equation:

$Q(t+90')=Q(t)/5\\\\a\cdot b^{-\frac{t+90'}{T} }=a\cdot b^{-\frac{t}{T} }/5\\\\ b^{-\frac{t+90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{t}{T} }b^{-\frac{90'}{T} }=b^{-\frac{t}{T} }/5\\\\b^{-\frac{90'}{T} }=\frac{1}{5}$

Now the last expression isn't enough to determine both T and b, but that also means that we have some freedom in how we choose them. What seems most simple is to pick $T=90'$ and thus we will get:

$b^{-1 }=\frac{1}{5}\\\\\frac{1}{b}= \frac{1}{5}\\\\b=5$

And that is our final result.

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3 years ago

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I hope I helped! ♥

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3 years ago

Am I correct on number 3

mrs_skeptik [129]

Yes your correct tttttttttttttttttttttttttttttttttttttttttttttttttttttttttt

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3 years ago

A book sold 39,400 copies in its first month of release. suppose this represents 8.9% of the number of copies sold to date. how

pishuonlain [190]

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3 years ago

Which equation represents the vertical asymptote of the graph?

Annette [7]

The curve is y equals 0 from negative x to negative y near x equals negative 8.

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→ x is almost equal to p but not p.

so in the denominator , it is x=-8,

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so vertical asymptote of curve is : x= -8

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3 years ago