Question

The area of a rectangle is 44 ft2 , and the length of the rectangle is 3 ft less than twice the width. find the dimensions of the rectangle.

Answer 1

Let width be x
Length: 2x-3 

44=(x)(2x-3) 
44=2x²-3x
0=2x²-3x-44 
0=(2x-11)(x+4) 

x=+11/2  or x=-4 

Since dimensions cannot be negative, we have to use 11/2 or 5.5 

The Width is 5.5ft , length is (2(5.5)-3)=8 ft

Hope I helped :)