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Iteru [2.4K]
3 years ago
12

PLEASE HELP!! You can get anything you want at Alberto's restaurant, as long as what you want is a sandwich with two different f

illings. There are nine fillings to choose from (turkey, ham, roast beef, cheese, tomatoes, peppers, sprouts, oranges, and licorice). How many different sandwiches can you order (including the ones that nobody in their right mind would order)?
Mathematics
2 answers:
sp2606 [1]3 years ago
6 0
Man what type weird asstronaut homework question on probability, during the SUMMER would have that many answers. This would take like a whole summer to do anyway. I dont believe any teacher would assign this to you, and, again, during the summer.
swat323 years ago
5 0

Answer: 36

Step-by-step explanation:

You might be interested in
A teacher needs 70 lengths of string cut to 40cm each. If balls of string are 10 m long, how many balls will be needed.
Genrish500 [490]

Answer:

3

Step-by-step explanation:

A ball is 10 meters. Since 100 centimeters are in a meter, each ball has 100*10 = 1000 centimeters.

The teacher needs 70 strings each 40 centimeters. The total amount they need is 70*40 = 2800 centimeters.

Since a ball has 1000 centimeters, 2800 centimeters will need 3 balls for a total of 3000 centimeters.

5 0
3 years ago
Solve the equation below for x. <br> 500 = 25e ^ (2x)
Zigmanuir [339]

Answer:

x = i π n + log(20)/2 for n element Z

Step-by-step explanation:

Solve for x:

500 = 25 e^(2 x)

500 = 25 e^(2 x) is equivalent to 25 e^(2 x) = 500:

25 e^(2 x) = 500

Divide both sides by 25:

e^(2 x) = 20

Take the natural logarithm of both sides:

2 x = 2 i π n + log(20) for n element Z

Divide both sides by 2:

Answer: x = i π n + log(20)/2 for n element Z

7 0
3 years ago
Whats the midpoint between 2 and 8​
ELEN [110]

Answer: 5

Step-by-step explanation:

8+2=10

10/2=5

7 0
3 years ago
Read 2 more answers
the initial vertical velocity of a rocket shot straight up is 42 meters per second. How long does it take for the rocket to retu
Snowcat [4.5K]
It takes 4.3 seconds for the rocket to return to earth.

The equation is:
0=-9.8t^2+v_0t+h_0
where -9.8m/sec² is the acceleration due to gravity, v₀ is the initial velocity, and h₀ is the initial height.  We will go from the assumption that the rocket is launched from the ground, so h₀=0, and we are told that the initial velocity, v₀, is 42.  This gives us:

0=-9.8t^2+42t

We will use the quadratic formula to solve this.  The quadratic formula is:
x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Plugging in our information we have:
t=\frac{-42\pm \sqrt{42^2-4(-9.8)(0)}}{2(-9.8)}&#10;\\&#10;\\=\frac{-42\pm \sqrt{1764-0}}{-19.6}&#10;\\&#10;\\=\frac{-42\pm \sqrt{1764}}{-19.6}&#10;\\&#10;\\=\frac{-42\pm 42}{-19.6}=\frac{-42-42}{-19.6} \text{ or } \frac{-42+42}{-19.6}&#10;\\&#10;\\=\frac{-84}{-19.6}\text{ or }\frac{0}{-19.6}&#10;\\&#10;\\=4.3\text{ or }0

x=0 is when the rocket is launched; x=4.3 is when the rocket lands.
8 0
3 years ago
Approximate pi plus the square root of 70 to the nearest hundredth.
stich3 [128]

Answer:

  11.51

Step-by-step explanation:

In general, a calculator is required to evaluate the irrational sum ...

  π + √70

<h3>Calculator result</h3>

The result from a readily-available online calculator is shown in the attachment.

  π + √70 ≈ 11.51

__

<em>Additional comment</em>

You have probably memorized pi to several digits: 3.1416. To obtain the required estimate means you need to approximate √70 to about the same level of precision.

For a number n = a² +b, the square root can be approximated by the continued fraction ...

  √n ≈ a +b/(2a +b/(2a +...))

Effectively, the root (r) can be iterated from the recursive formula ...

  r' = a +b/(a +r)

For √70, we have 70 = 8² +6   ⇒   a=8, b=6

If the initial approximation of the root is r0≈a=8, then a couple of iterations gives ...

  r1 = 8 + 6/(8 +r0) = 8 + 6/(8 +8) = 8 3/8

  r2 = 8 + 6/(8 +r1) = 8 +6/(8 +8 3/8) = 8 48/131

This has sufficient accuracy for the purpose. The decimal equivalent of the sum then becomes ...

  3.1416 +8.3664 = 11.5080 ≈ 11.51

5 0
1 year ago
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