Question

The terminal side of 0 is in quadrant II and cos 0 = -5/13. What is sin 0?

Answer 1

Answer:

$\displaystyle \sin\theta=\frac{12}{13}$

Step-by-step explanation:

We are given that:

$\displaystyle \cos\theta =-\frac{5}{13}\text{ where \theta is in QII}$

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using the Pythagorean Theorem, solve for the opposite side (we can ignore the negative for now):

$o=\sqrt{13^2-5^2}=12$

And since θ is in QII, sine is positive, and cosine and tangent are both negative.

Sine is the ratio of the opposite side to the hypotenuse. Therefore:

$\displaystyle \sin\theta=\frac{12}{13}$

Answer 2

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