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xenn [34]
3 years ago
5

6 yd, 1 ft = ___ ft A) 7 B) 12 C) 19 D) 36 .<. plz halp

Mathematics
1 answer:
vodomira [7]3 years ago
4 0
The answer is 19 feet because 6 yards is equal to 18 feet and then add the 1 foot and you get 19 feet.

So the answer is 19

Answer:19
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What are the coordinates of the endpoints of the midsegment for △LMN that is parallel to LN¯¯¯¯¯ ?
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The coordinates of the endpoints of the midsegment for △LMN that is parallel to LN are (3, 4.5) and (3, 3).

Explanation:

Given that △LMN

We need to determine the coordinates of the endpoints of the midsegment for △LMN that is parallel to LN

The midsegment of the triangle parallel to side LN is the midsegment connecting the midpoint of side LM and the midpoint of side MN.

The midpoint of LM is given by

\left(\frac{0+6}{2}, \frac{5+4}{2}\right)

Simplifying, we get,

(\frac{3}{2}, \frac{9}{2} )=(3,4.5)

The midpoint of MN is given by

\left(\frac{0+6}{2}, \frac{2+1}{2}\right)=(3,3)

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3 years ago
When does an absolute value equation have no solution? Help pls
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5 0
3 years ago
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A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

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A.)Consider

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f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

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Since, the function f(g(x)) is not defined for x=0.

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For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



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4 years ago
Need answers ASAP<br> !help me please
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Write the following in exponent form.
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