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3 years ago

For the following systems of equations, match each diagram on the left with its solution on the right.

Mathematics

2 answers:

mihalych1998 [28]3 years ago

8 0

Answer:

1. (2,1)

2. (6,-1)

3.(-2,3)

elixir [45]3 years ago

7 0

Answer:

1. (2,1)

2. (6,-1)

3. (-2,3)

Step-by-step explanation:

Each of the answer is consistent system because the lines intersect at one point, which is one solution.

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WILL MARK BRAINLIST!!!!

Lesechka [4]

Answer:

Step-by-step explanation:

I had this answer

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3 years ago

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1) Slope =-1, y-intercept = 0

Dima020 [189]

Answer:

1. C 2.D 3.D 4.A

Step-by-step explanation:

The first one would be C because the slope is -1, which can also be -x and the y-intercept is 0, meaning you don't need to add or subtract anything.

The second one is D because the slope is -3, meaning it's -3x, and the y-intercept is positive, meaning you add 5.

The third one is D because the slope is 5/4, which is 5/4x and the y-intercept is positive 3, meaning you add 3.

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3 years ago

Evaluate the expression for x = -2, y = 3, z = -4. -4x + 5y + 6z *

babunello [35]

Answer:

-1

Step-by-step explanation:

Plug in given values

-4x + 5y + 6z

-4(-2) + 5(3) + 6(-4)

8 + 15 -24

23-24

-1

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3 years ago

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McAllister et al. (2012) compared varsity football and hockey players with varsity athletes from noncontact sports to determine

jonny [76]

Answer:

$t _{critical} = 1.760$

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

$H_o: \mu_1 - \mu_2 = 0$

Alternative hypothesis;

$H_a : \mu_1 - \mu_2 > 0\\$

The pooled variance t-Test would have been determined if the population variance are the same.

$S_p^2 = \dfrac{(n_1-1)S_1^2+(n_2-1)S^2_2}{(n_1-1)+(n_2-1)}$

$S_p^2 = \dfrac{(8-1)2.507^2+(8-1)2.8282^2}{(8-1)+(8-1)}$

$S_p^2 = 7.14$

The t-test statistics can be computed as:

$t= \dfrac{(x_1-x_2)-(\mu_1 - \mu_2)}{\sqrt{Sp^2 ( \dfrac{1}{n} +\dfrac{1}{n_2})}}$

$t= \dfrac{(9-6)-0}{\sqrt{7.14 ( \dfrac{1}{8} +\dfrac{1}{8})}}$

$t= \dfrac{3}{1.336}$

t = 2.2450

Degree of freedom $df = (n_1 -1) + ( n_2 +1 )$

df = (8-1)+(8-1)

df = 7 + 7

df = 14

At df = 14 and ∝ = 0.05;

$t _{critical} = 1.760$

Decision Rule: To reject the null hypothesis if the t-test is greater than the critical value.

Conclusion: We reject $H_o$ and there is sufficient evidence to conclude that the test scores for contact address s less than Noncontact athletes.

To calculate r²

The percentage of the variance is;

$r^2 = \dfrac{t^2}{t^2 + df}$

$r^2 = \dfrac{2.2450^2}{2.2450^2 + 14}$

$r^2 = \dfrac{5.040025}{5.040025+ 14}$

$r^2 = 0.2647$

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3 years ago

Can you please help I don’t understand

Ludmilka [50]

Answer:

( -4 , -4 )

Step-by-step explanation:

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3 years ago

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