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harkovskaia [24]
3 years ago
12

Kyle plans to estimate the area of the figure below by identifying the full and partial squares that make up the figure.

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

The answer is one hundred percent D

Step-by-step explanation:

Hi

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If f(x) = 3x-1 and g(x)= x+2 find (f-g)(x)​
wariber [46]

Answer:

2x-3

Step-by-step explanation:

f(x) = 3x-1

g(x) = x+2

Find (f-g)(x), this means we need to subtract g from x.

(3x-1) - (x+2)

Subtract the like terms:

3x -x = 2x

-1 -2 = -3

Combine them to get 2x-3

7 0
3 years ago
What is the solution to the equation? sqrtx + 3 = 12 HINT: It's not C.
oksano4ka [1.4K]
B.) 81
sq rt of x= 12-3
sq rt of x=9
take the ^2 of both sides to get rid of the sq root
x^2= (9)^2
=81
7 0
3 years ago
A rectangular board has an area of 648 square centimeters. The triangular part of the board has an area of 162 square centimeter
maksim [4K]

Answer:

25%.

Step-by-step explanation:

Let E be the event that the dart lands inside the triangle.

We have been given that a rectangular board has an area of 648 square centimeters. The triangular part of the board has an area of 162 square centimeters.

We know that probability of an event represents the chance that an event will happen.

\text{Probability}=\frac{\text{Favorable no. of events}}{\text{Total number of possible outcomes}}

\text{Probability that dart lands inside the triangle}=\frac{\text{Area of triangle}}{\text{Area of rectangle}}

\text{Probability that dart lands inside the triangle}=\frac{162}{648}

\text{Probability that dart lands inside the triangle}=0.25

Convert into percentage:

0.25\times 100\%=25\%

Therefore, the probability that dart lands inside the triangle is 25%.

7 0
3 years ago
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4 0
3 years ago
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Golf-course designers have become concerned that old courses are becoming obsolete since new technology has given golfers the ab
zhenek [66]

Answer:

test statistic is ≈ -0.36

p-value is  ≈ 0.64

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

Step-by-step explanation:

a hypothesis test where H_0: mu = 235 and H_1:mu > 235

test statistic can be calculated as follows:

z=\frac{X-M}{\frac{s}{\sqrt{N} } } where

  • sample mean driving distance (233.8 yards)
  • M is the average expected distance that the average golfer can hit the ball under null hypothesis. (235 yards)
  • s is the standard deviation (46.6 yards)
  • N is the sample size (192)

Then test statistic is z=\frac{233.8-235}{\frac{46.6}{\sqrt{192} } } =-0.3568

p-value is  0.64 >0.05

There is no significant evidence that the average golfer can hit the ball more than 235 yards on average.

6 0
3 years ago
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