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vivado [14]
2 years ago
9

Five members of the football team and five members of the track team ran the 100- meter dash. Their times are listed in the tabl

e below:
Mathematics
1 answer:
Bumek [7]2 years ago
8 0
Where is the table? Even if not, you would use a variable or use the butterfly method to see who has the biggest average.
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The usual price of a sweatshirt is 18$, what is its sale price
german

Answer:

$19.08

Step-by-step explanation:

18 + 6% = (18 x 1.06) = 19.08

8 0
3 years ago
4.702 x 10–4 i need this answer in standard notation<br> .
nevsk [136]
The answer should be 0.0004702
6 0
3 years ago
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1/3 of 7 as a fraction
klio [65]
Hey There! Whoever we see the keyword “of”, we know that it’s multiplication Therefore we’re multiplying 1/3 and 7/1 that gives us 7/3

3 0
2 years ago
Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: nequals45 and x overbar
Tomtit [17]

Answer: (141.1, 156.48)

Step-by-step explanation:

Given sample statistics : n=45

\overline{x}=148.79\text{ lb}

\sigma=31.37\text{ lb}

a) We know that the best point estimate of the population mean is the sample mean.

Therefore, the best point estimate of the mean weight of all women = \mu=148.79\text{ lb}

b) The confidence interval for the population mean is given by :-

\mu\ \pm E, where E is the margin of error.

Formula for Margin of error :-

z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}

Given : Significance level : \alpha=1-0.90=0.1

Critical value : z_{\alpha/2}=z_{0.05}=\pm1.645

Margin of error : E=1.645\times\dfrac{31.37}{\sqrt{45}}\approx 7.69

Now, the 90% confidence interval for the population mean will be :-

148.79\ \pm\ 7.69 =(148.79-7.69\ ,\ 148.79+7.69)=(141.1,\ 156.48)

Hence, the 90​% confidence interval estimate of the mean weight of all women= (141.1, 156.48)

3 0
2 years ago
6 points are placed on the line a , 4 points are placed on the line b . How many triangles is it possible to form such that thei
BaLLatris [955]

Answer:

96

Step-by-step explanation:

Using side b as the base, 4 points makes 3 bases (the space in between).  With three bases, you can have 3 bases of 1 segment, 2 bases of 2 segments, and 1 base of 3 segments.  This equals 6 bases. Each of these can connect to a point on line a. 6x6=36

Using side a as the base, 6 points makes 5 bases.  With 5 bases, you can have 5 bases of 1 segment, 4 bases of 2 segments, 3 bases of 3 segments, 2 bases of 4 segments, and 1 base of 5 segments.  This equals 15 bases.  Each of these can connect to a point on line b.  15x4=60

36+60=96

5 0
2 years ago
Read 2 more answers
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