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3 years ago

4.702 x 10–4 i need this answer in standard notation .

Mathematics

2 answers:

nevsk [136]3 years ago

6 0

The answer should be 0.0004702

emmainna [20.7K]3 years ago

6 0

4.702*10^-4=4.702*.0001=.0004702

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Please im begging you guys please please do it for me please

Tasya [4]

When Jamie has $200 to purchase skateboard equipment, he will have spent more than 50 percent.

<h3>How to calculate the percentage?</h3>

From the information given, the total amount spent will be:

= $100 + $60 + $30 + $20 + $20 + $50 + $115

= $395

Since Jamie has $200 to purchase skateboard equipment, the percentage will be:

= 200/395

= 0.51

= 51%

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2 years ago

AB is congruent to DE because segment DE was constructed so that DE = AB. BC is congruent to EF because segment EF was construct

Alex Ar [27]

DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

<h3>Congruent shape</h3>

Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.

Given that DE = AB and BC = EF.

In right triangle DEF, using Pythagoras:

DF² = DE² + EF²

Also, In right triangle ABC, using Pythagoras:

AC² = AB² + BC²

But DE = AB and EF = BC, hence:

AC² = DE² + EF²

AC² = DF²

Taking square root of both sides, hence:

AC = DF

Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.

Find out more on Congruent shape at: brainly.com/question/11329400

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3 years ago

a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l

GrogVix [38]

Answer:

$\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}$

Step-by-step explanation:

The equation of a line:

$y=mx+b$

We have

$m=\dfrac{2}{3}$

substitute:

$y=\dfrac{2}{3}x+b$

The formula of a distance between a point and a line:

General form of a line:

$Ax+By+C=0$

Point:

$(x_0,\ y_0)$

Distance:

$d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}$

Convert the equation:

$y=\dfrac{2}{3}x+b$ |<em>subtract $y$ from both sides</em>

$\dfrac{2}{3}x-y+b=0$ |<em>multiply both sides by 3</em>

$2x-3y+3b=0\to A=2,\ B=-3,\ C=3b$

Coordinates of the point:

$(0,\ 0)\to x_0=0,\ y_0=0$

substitute:

$d=4$

$4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}$

$4=\dfrac{|3b|}{\sqrt{13}}\qquad|$ |<em>multiply both sides by $\sqrt{13}$ </em>

$4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}$ |<em>divide both sides by 3</em>

$b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}$

Finally:

$y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}$

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3 years ago

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ratelena [41]

Answer:

Step-by-step explanation:

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3 years ago

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umka2103 [35]

Answer:1234567890

Step-by-step explanation:101112131415161789995657

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3 years ago