Please Answer The Ones That Are Circled. (DON'T PUT DECIMALS FOR THE DIVISION PUT REMAINDER)if u can't see any tell me.
1 answer:
Lesson 2.7:
1) / divide 195 by 18 to get 10.833.
/ to get the whole number, round up to get '11'.
11 cartons
Lesson 2.8:
3)
÷ 
= 7
5) 6,681 ÷ 53 = 126 with a remainder of 3
Lesson 2.9:
1) / let 'x' equal the inches of snow that reidville gets
/ '12x' equal the inches of snow that greenboro gets
/ you should set up the problem like:
/ add 'x + 12x' to get '13x'.
/ divide both sides by '13'.
/ 5 goes into 13 to get 65. simplify the fraction to '5'.
/ x = 5
Reidville gets 5 inches of snow
2) / let 'x' equal the miles ansley ran in one month
/ you should set up the problem like:
/ add '15x + x' to get '16x'
/ divide both sides by '16'
/ 12 goes into 16 to get 192. simplify the fraction to 12.
/ x = 12
Ansley runs 180 miles (Zack only runs 12)
1) / divide 195 by 18 to get 10.833.
/ to get the whole number, round up to get '11'.
11 cartons
Lesson 2.8:
3)
5) 6,681 ÷ 53 = 126 with a remainder of 3
Lesson 2.9:
1) / let 'x' equal the inches of snow that reidville gets
/ '12x' equal the inches of snow that greenboro gets
/ you should set up the problem like:
/ add 'x + 12x' to get '13x'.
/ divide both sides by '13'.
/ 5 goes into 13 to get 65. simplify the fraction to '5'.
/ x = 5
Reidville gets 5 inches of snow
2) / let 'x' equal the miles ansley ran in one month
/ you should set up the problem like:
/ add '15x + x' to get '16x'
/ divide both sides by '16'
/ 12 goes into 16 to get 192. simplify the fraction to 12.
/ x = 12
Ansley runs 180 miles (Zack only runs 12)
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Answer:
The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.
The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.
Step-by-step explanation:
The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.
In a sample of 20 items there are 4 defective items.
The probability of selecting a defective item is:
A random sample of <em>n</em> = 3 items are selected at random.
The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.
The variance of a Binomial distribution is:
Compute the variance of <em>X</em> as follows:
Compute the standard deviation (σ (X)) as follows:
Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.
Now compute the variance of (20 - X) as follows:
Compute the standard deviation of (20 - X) as follows:
Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.