Ask question

Ask question

All categories

3 years ago

10

What is 832.248 rounded to the nearest tenth? A. 830 B. 832.2 C. 832.25 D. 832.3

1 answer:

OleMash [197]3 years ago

4 0

Hi there.

To start, we have to understand where the ten the place is.

Hint: it's 1 place behind the decimal point.

Now we need to know what numbers behind the tenths place make it round up or down.

If the number behind it is 4 or under, round down.

5 & up, round up.

In this case, 830.248 has 2 numbers behind the decimal, so we have to round those THEN the 2 in the tenths place.

830.25 to 830.3

Your answer is D. 830.3

I know this was lengthy, sorry. Just wanted to explain :p

You might be interested in

Solve the inequality x/5-3<0

Kisachek [45]

Answer:

x < 15

Step-by-step explanation:

$\frac{x}{5}$ - 3 < 0 ( add 3 to both sides )

$\frac{x}{5}$ < 3 ( multiply both sides by 5 to clear the fraction )

x < 15

7 0

3 years ago

Find the measure or the missing angle, please

ExtremeBDS [4]

IK its an obtuse angleeee if that helps

3 0

3 years ago

Apply the distributive property to write an equivalent expression.

aleksley [76]

Answer:

6x + 48

Step-by-step explanation:

multiply each term inside the () by 6

6x + 6*8

7 0

3 years ago

When finding the 9th term in a geometric sequence with a common ratio of 2 and a first

Zarrin [17]

Answer:

8

Step-by-step explanation:

Nth term of a geometric sequence is given as:

$t_n = a r^{(n-1)}$ ...(1)

Plugging n = 9, a = 3 and r = 2 in the above equation, we find:

$t_9 = (3) (2)^{9-1}$

$t_9 = (3) (2)^{8}$ ... (2)

Comparing equations (1) & (2), we obtan:

(n - 1) = 8

5 0

3 years ago

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago