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agasfer [191]
3 years ago
12

Donna Meagle notices that on 12 out of 14 days, her clumsy coworker Jerry Gergich spills his lunch on himself. She concludes tha

t the probability that Jerry will spill his lunch on himself tomorrow is about 86%. Is this an example of a theoretical or empirical probability?
Select one:
a. Empirical
b. Theoretical
Mathematics
1 answer:
pantera1 [17]3 years ago
6 0

Answer:

It is an example of an empirical probability.

Step-by-step explanation:

The empirical probability, also called experimental probability of an event is the ratio of the number of outcomes in which a specified event occurs to the total number of trials, not in a theoretical sample space but in an actual experiment.

Theoretical probability is probability that is determined on the basis of reasoning.

It is evident that the probability in the question was arrived at after the outcome of 14 days of whether Jerry Gergich spilled his lunch on himself or not.

It's an actual result of an experiment, hence the 12/14 = 0.86 = 86% that he spills his lunch on himself tomorrow.

Hope this Helps!!!

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Solve the following problems. Remember that all reasoning must be explained, and all steps of math work must be shown!
iris [78.8K]

Answer to Question 1:

<OGE (also m˚) = 19˚

Step-by-step explanation:

We know that all the angles in a triangle add up to 180˚.

<u>Given:</u>

<EGO = 71˚

<OEG = 90˚ (the angle forms a right angle because line EG is perpendicular to point O)

<u>To Solve:</u>

⇒ Since we know two angles, we should know the third; and they all add up to 180˚. This can be written as:

71˚ + 90˚ + <OGE = 180˚

⇒ Solve for <OGE by simplifying:

161˚ + <OGE = 180˚

⇒ Subtract 161˚ from both sides to get:

161˚ − 161˚ + <OGE = 180˚ − 161˚

⇒ Isolate <OGE:

<OGE = 19˚

<u>Answer:</u> <OGE (also m˚) = 19˚

Answer:

<OAC (also x˚) = 50˚

<OCB (also y˚) = 90˚

Step-by-step explanation:

–<u>How to solve for <OCB (also y˚)</u>

Just by looking, you can already tell that <OCB equals 90˚ because it forms a right angle.

<u>Answer:</u> <OCB (also y˚) = 90˚

–<u>How to solve for <OAC (also x˚)</u>

<u>Given (and what we can already know):</u>

<AOC = 40˚

<OCA = 90˚

⇒ Reason: Line AB is a straight line and a straight line equals 180˚. We already know on side of the line because <OCB is 90˚, and so the other side, <OCA, should also be 90˚, since the both sides that make up the straight line equal 180˚ (90˚ + 90˚ = 180˚). You can also tell that <OCA forms a right angle in the triangle because line AB is perpendicular to point O, and right angles are 90˚.

<u>To Solve:</u>

⇒ Since we know two angles in the triangle, we should know the third; and they all add up to 180˚. This can be written as:

40˚ + 90˚ + <OAC = 180˚

⇒ Solve for <OAC by simplifying:

130˚ + <OAC = 180˚

⇒ Subtract 130˚ from both sides to get:

130˚ − 130˚ + <OAC = 180˚ − 130˚

⇒ Isolate <OAC:

<OAC = 50˚

<u>Answer:</u> <OAC (also x˚) = 50˚

I hope you understand and that this helps with your question! :)

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