$150 as a percentage of $500

2 answers:

7 0

Method 1

$\begin{array}{cccc}\$500&-&100\%&|divide\ both\ sides\ by\ 10\\\$50&-&10\%&|multiply\ both\ sides\ by\ 3\\\$150&-&30\%\end{array}$

Answer: $150 is 30% of $500

Method 2

$\begin{array}{ccc}\$500&-&100\%\\\$150&-&p\%\end{array}\ \ \ |cross\ multiply\\\\500p=150\cdot100\\500p=15000\ \ \ \ |divide\ both\ sides\ by\ 500\\p=30$

Answer: $150 is 30% of $500

Method 3

$\dfrac{\$150}{\$500}\cdot100\%=\dfrac{15}{50}\cdot100\%=\dfrac{15}{1}\cdot2\%=15\cdot2\%=30\%$

Answer: $150 is 30% of $500

saveliy_v [14]4 years ago

3 0

I think the answer is 30

Because I did 150÷500×100

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Solve the inequality for x 3^(6x+18)<27^(3x)

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Answer:

$\displaystyle x > 6$

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Order of Operations: BPEMDAS

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Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle 3^{6x + 18} < 27^{3x}$

Step 2: Solve for x

Rewrite: $\displaystyle 3^{6x + 18} < 3^{3(3x)}$
Set: $\displaystyle 6x + 18 < 3(3x)$
Factor: $\displaystyle 3(2x + 6) < 3(3x)$
[Division Property of Equality] Divide 3 on both sides: $\displaystyle 2x + 6 < 3x$
[Subtraction Property of Equality] Subtract 3x on both sides: $\displaystyle -x + 6 < 0$
[Subtraction Property of Equality] Subtract 6 on both sides: $\displaystyle -x < -6$
[Division Property of Equality] Divide -1 on both sides: $\displaystyle x > 6$