Write a real word problem that cold be solved by using the equation 3x- 25= 125

2 answers:

6 0

<span>Two teams are playing basketball. Team 1 scored 3.5 times the number of points per basket. Team 2 scored 8 times the number of points per basket. They would've each scored the same amount of points if Team 1 had scored 54 more points.
Solve:
54+3.5x=8x :Write out the equation
-3.5x -3.5x :Subtract 3.5x from both sides to isolate the variable
54=4.5x :Simplify
/4.5 /4.5 :Divide by 4.5 on both sides
12=x :Answer=12
Next you would find each team's score:
8x= 8(12)= 96 :substitute and solve
Each team score is 96 points
(Note: Since each team score was equal, you don't have to solve for each team, just one and preferably the easier one, and that is the score that each team scored.) </span>

pychu [463]4 years ago

5 0

Answer:

If we have a problem,

In a school there are 125 girls which is 25 less than 3 times of the number of boys how many boys are there ?

Let x be the number of boys,

So, the number of girls = 3 × number of boys - 25

= 3x - 25,

∵ Number of girls = 125

⇒ 3x - 25 = 125

Hence, the above real word problem could be solved by the given equation.

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Suppose the position of an object moving horizontally after t seconds is given by the following functions s=f(t), s equals f , o

Scilla [17]

Answer:

(a) The graph of position function is shown below.

(b) The velocity function is $v(t)=-2t+4$ and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(d) The acceleration of the object is -2 when its velocity is zero.

(e) The speed is not increasing at any interval because the acceleration is constant.

Step-by-step explanation:

(a)

The given function is

$f(t)=-t^2+4t-3; 0\leq t\leq 5$

The position of an object moving horizontally after t seconds is given by

$s=f(t)=-t^2+4t-3$

The graph of position function is shown below.

(b)

Differentiate the position function with respect to time to find the velocity function.

$v=f'(t)=-2t+4$

Put v=0 to find the time when the object is stationary.

$0=-2t+4$

$2t=4$

$t=2$

The object is stationary at t=2 because the velocity of the object is 0 at t=2.

The velocity function is $v(t)=-2t+4$ and the graph of position function is shown below. The object is stationary at t=2, moving to the right at t>2, and moving to the left at t<2.

(c)

The velocity function is

$v=f'(t)=-2t+4$

Substitute t=1 in the above function.

$v=f'(1)=-2(1)+4=2$