6 numbers per cube
if one is a 1, then the other one has to be a 2, 4 or 6 to be an odd sum
1+2=3, 1+4=5,1+6=7
since there are 3 numbers you can get that would be a 3/6 ( reduce to 1/2) probability
so 1/2 probability
F(x) = -5 x + 10
Then
f(-2) = -5(-2) + 10
= 10 + 10
= 20
The missing step 2 should be;
The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8
The missing step 6 would be that; 76 - 1.85
<h3>How to Solve Mathematical Order of Operations?</h3>
We want to know the steps to solving the expression the quantity of the sum of six squared plus two divided by the absolute value of negative 0.5 − 14.8 ÷ 8
This can be expressed as;
6² + 2 ÷ |-0.5| - 14.8 ÷ 8
Thus, the next step which is step 2 should be;
The quantity of the sum of thirty six plus two divided by 0.5 − 14.8 ÷ 8
The missing step 6 would be that;
76 - 1.85
Read more about Order of Operations at; brainly.com/question/27529825
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Answer:
the probability that the shipment is accepted is 0.8865
Step-by-step explanation:
Given the data in the question;
N = 86, n/d = 5 and n = 2
now, without replacement
the probability that the shipment is accepted will be;
probability that the shipment is accepted = probability that non is defectives
so p( non is defective ) = ( (86-5)/86) × ((86-5-1)/(86-1))
p( non is defective ) = ( 81 / 86) × (80/85)
p( non is defective ) = 0.8865
Therefore, the probability that the shipment is accepted is 0.8865
Answer: 0.9617
Step-by-step explanation:
Given : The proportion of adults use their phones in meetings or classes : p=0.57
Number of adults randomly selected : n= 9
Let x be the random variable that represents the number of adults use their phones in meetings or classes.
By using binomial probability formula, to find the probability of getting success in x trials.
The probability that at least 3 of them use their smartphones in meetings or classes will be :-
Hence, the required probability is 0.9617 .
