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kvasek [131]
3 years ago
15

HELPPPPPPPPPPPP

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

25cm

Step-by-step explanation:

one the possibility 36 - 11 =25 the answer is 25

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I need help with #8. I need to use the quadratic formula. I have a calculator that is programmed for the quadratic formula so al
GuDViN [60]

Answer:

  x = 14

Step-by-step explanation:

Extend line AB so that it intersects ray CE at point G. Then angles BGC and BAD are "alternate interior angles", hence congruent.

The angle at B is exterior to triangle BCG, and is equal to the sum of the interior angles at C and G:

  138 = (376 -23x) +(x^2 -8x)

Subtracting 138 and collecting terms we have ...

  x^2 -31x +238 = 0

For your calculator, a=1, b=-31, c=238.

__

<em>Additional comment</em>

You will find that the solutions to this are x = {14, 17}. You will also find that angle BCE will have corresponding values of 54° and -15°. That is, the solution x=17 is "extraneous." It is a solution to the equation, but not to the problem.

For x=14, the marked angles are A = 84°, C = 54°.

8 0
3 years ago
Write an equation to represent the following statement.
svetoff [14.1K]

Answer/explanation:

60=5k 

Is the equation because the word is means equals, so we add an equal sign after the 60. Five times greater simply means multiply so we multiply 5 and k.

To solve the equation, you would need to divide both sides by 5 to isolate the variable

60/5=5k/5

12=k 

7 0
3 years ago
Line l is a perpendicular bisector of line segment A C. It intersects line segment A C at point B. Line l also contains points D
N76 [4]

Answer:

First one is DC

Second one is AB.

Step-by-step explanation:

Just did them on edge.

3 0
4 years ago
Read 3 more answers
Find the 10th term of the geometric sequence whose common ratio is 2/3 and whose first term is 3.
Sergeu [11.5K]

Answer:

\frac{512}{6561}

Step-by-step explanation:

1) if according to the condition a₁=3 and r=2/3, then a₁₀ can be calculated as:

a₁₀=a₁*r⁹;

2) according  to the rule above:

a₁₀=3*(2/3)⁹=512*3/(6561*3)=512/6561.

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2 years ago
How many strings of eight uppercase English letters are there if no letter can be repeated?
zepelin [54]
....................................3.....................................
7 0
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