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3 years ago

In bullet points: explain the difference between thermal energy, heat and temperature.

Chemistry

1 answer:

sergeinik [125]3 years ago

3 0

Thermal Energy- is the energy that comes from heat. This heat is generated by the movement of tiny particles within an object. The faster these particles move, the more heat is generated.

Heat-energy is the result of the movement of tiny particles called atoms, molecules or ions in solids, liquids and gases. Heat energy can be transferred from one object to another. The transfer or flow due to the difference in temperature between the two objects.

Temperature- is a measure of how hot or cold something is; specifically, a measure of the average kinetic energy of the particles in an object, which is a type of energy associated with motion.

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We have air (21% O2 and 79% N2) at 23 bar and 30 C. 4. What is the ideal molar volume (m^3/kmol)? a. b. What is the Z factor? Wh

k0ka [10]

Answer:

The ideal molar volume is $\frac{V}{n} =V_z= 0.001095 \ m^3/mol$

The Z factor is $Z = 0.09997$

The real molar volume is $\frac{V_r}{n} = V_k= 0.0001095\ \frac{m^3}{mol}$

Explanation:

From the question we are told that

The pressure is $P = 23 \ bar = 23 *10^5 Pa$

The temperature is $T = 30 ^ oC = 303 \ K$

According to the ideal gas equation we have that

$PV = nRT$

=> $\frac{V}{n}=V_z= \frac{RT}{P}$

Where $\frac{V}{n }$ is the molar volume and R is the gas constant with value

$R = 8.314 \ m^3 \cdot Pa \cdot K^{-1}\cdot mol^{-1}$

substituting values

$\frac{V}{n} =V_z= \frac{ 8.314 * 303}{23 *10^{5}}$

$\frac{V}{n} =V_z= 0.001095 \ m^3/mol$

The compressibility factor of the gas is mathematically represented as

$Z = \frac{P * V_z}{RT}$

substituting values

$Z = \frac{23 *10^{5} * 0.001095}{8.314 * 303}$

$Z = 0.09997$

Now the real molar volume is evaluated as

$\frac{V_r}{n} = V_k= \frac{Z * RT }{P}$

substituting values

$\frac{V_r}{n} = V_k= \frac{0.09997 * 8.314 * 303}{23 *10^{5}}$

$\frac{V_r}{n} = V_k= 0.0001095\ \frac{m^3}{mol}$

8 0

3 years ago

What group is the element barium(Ba) In?<br>A. 1<br>B. 6<br>C. 56<br>D. 4

LenaWriter [7]

Ummmmmmmmmmm 56 yes 56

7 0

2 years ago

If further increases in substrate concentration do not result in further increases in reaction rate, then an enzyme is likely

igor_vitrenko [27]

Given what we know, we can confirm that if further increases in substrate concentration do not result in further increases in reaction rate, then an enzyme is likely saturated.

<h3>What does it mean for an enzyme to be saturated?</h3>

Enzymes work by binding to the substrate in specific zones of the enzyme. The zones are known as the active sites on enzymes. Since enzymes have a limited amount of these zones, once they are all bonded to a substrate, we can say that it is saturated.

Therefore, the saturation of enzymes allows us to explain how further increases in substrate concentration do not result in further increases in reaction rate.

To learn more about enzymes visit:

brainly.com/question/24811456?referrer=searchResults

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2 years ago

Dipole-induced dipole attractions exist between molecules of water and molecules of gasoline, yet these two substances do not mi

lana [24]

Gasoline is predominantly octane, C8H18. Something like soap would be a great homogenizer. Soap is composed of a long hydrocarbon chain with a tiny, highly polar tip on one end. Usually, the soap is the anion of a salt, NaX. This allows the polar end of the soap to stick to water, while the nonpolar end sticks to the oil.

$\frac{kg*m*m}{m^3*s*\mu}=1=\frac{kg}{m*s*\mu}$

$\mu=\frac{kg}{m*s}$

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3 years ago

Which metal atom below would Not be involved in formation of a Type II Compound?

BartSMP [9]

In formation of a Type II Binary Compound, the metal atom present is<span> NOT</span> found in either Group 1 or Group 2 on the periodic table. For the choices, Ba is under Group 2 on the periodic table, which makes it the atom not involved in formation of type II compounds. The answer is B.

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3 years ago